All categories

2 years ago

Factorise completely X^4-5X^3+6X^2+4X+8≤0

Mathematics

1 answer:

love history [14]2 years ago

4 0

Answer:

I think the answer is x-11x^5+12x

You might be interested in

Eight decreased by three times the sum of a number and six Write as an algebraic expression

Advocard [28]

8-3(x+6)

explanation:

it just makes sense lol but also bc “8 decreased by three” means “8 minus 3”

then “times” means “multiply”

then “a sum” means “addition”

then “a number” since we don’t know what a number is then we use “x”

“and” means “addition”

“a number and six” means “x+6”

3 0

2 years ago

(Lots of points)PLEASE HELP ME Due today at 8:59 in Texas

IceJOKER [234]

Answer:

6.) So 8 of 24 hours is 1/3. So the percent of his time used was 33.33333 . . % (etc)

7.) The easiest way to figure out a percentage is dividing it. So if it was 30 hit out of 75 people, then divide 30 by 75. So 40% of them got hit.

Hope that helps

6 0

2 years ago

A pan is heated to 393°F, then removed from the heat and allowed to cool in a kitchen where the room temperature is a constant 6

deff fn [24]

Answer:

The approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

Step-by-step explanation:

The formula for D, the difference in temperature between the pan and the room after t minutes is:

$D = 324\cdot e^{-0.05t}$

Compute the approximate difference in temperature between the pan and the room after 9 minutes as follows:

$D = 324\cdot e^{-0.05t}$

$=324\times e^{-0.05\times 9}\\\\=206.59$

Then the approximate temperature of the pan after it has been away from the heat for 9 minutes is:

D = P - R

206.59 = P - 69

P = 206.59 + 69

P = 275.59°F

Thus, the approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

6 0

2 years ago

6x^2-5x+1 Factor polynomial

Tamiku [17]

6x²-5x+1
=6x²-3x-2x+1
=3x(2x-1)-1(2x-1)
=(3x-1)(2x-1)

8 0

2 years ago

Evaluate 8^-2 pls only real answers

Burka [1]

Step-by-step explanation:

By Law of Indices,

8^(-2) = 8^0 / 8^2

= 1 / 64.

8 0

2 years ago