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olga nikolaevna [1]
2 years ago
12

Solve the system of equations -x+ 2y = –11 and 5x – 8y = 39 by combining the equations.

Mathematics
1 answer:
Alchen [17]2 years ago
3 0

Answer:

x=-5, y=-8. (-5, -8).

Step-by-step explanation:

-x+2y=-11

5x-8y=39

---------------

5(-x+2y)=5(-11)

5x-8y=39

---------------------

-5x+10y=-55

5x-8y=39

--------------------

2y=-16

y=-16/2

y=-8

-x+2(-8)=-11

-x-16=-11

-x=-11+16

-x=5

x=-5

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Answer:

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Step-by-step explanation:

20-5=15 - change in numbers

15/20×100%= 75%

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3 years ago
Can someone help me with this ​
Nataly_w [17]

Answer:

  b, e

Step-by-step explanation:

a, b) ordinarily, we claim the variable on the vertical axis is a function of the variable on the horizontal axis. By that claim, <em>temperature is a function of time</em>.

If the graph passed the horizontal line test (a horizontal line intersects in one place), then we could also say time is a function of temperature. The graph does not pass that test, so we cannot make that claim.

c) The graph has negative slope between 4:00 and 5:00. Temperature is decreasing in that interval, not increasing.

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In a certain section of Southern California, the distribution of monthly rent for a one-bedroom apartment has a mean of $2,275 a
KATRIN_1 [288]

Answer:

100% probability of selecting a sample of 65 one-bedroom apartments and finding the mean to be at least $2,095 per month

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of $2,275 and a standard deviation of $290.

This means that \mu = 2275, \sigma = 290

Sample of 65:

This means that n = 65, s = \frac{290}{\sqrt{65}}

Finding the mean to be at least $2,095 per month

This is 1 subtracted by the p-value of Z when X = 2095. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2095 - 2275}{\frac{290}{\sqrt{65}}}

Z = -5

Z = -5 has a p-value of 0.

1 - 0 = 1

100% probability of selecting a sample of 65 one-bedroom apartments and finding the mean to be at least $2,095 per month

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