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olga nikolaevna [1]
2 years ago
12

Solve the system of equations -x+ 2y = –11 and 5x – 8y = 39 by combining the equations.

Mathematics
1 answer:
Alchen [17]2 years ago
3 0

Answer:

x=-5, y=-8. (-5, -8).

Step-by-step explanation:

-x+2y=-11

5x-8y=39

---------------

5(-x+2y)=5(-11)

5x-8y=39

---------------------

-5x+10y=-55

5x-8y=39

--------------------

2y=-16

y=-16/2

y=-8

-x+2(-8)=-11

-x-16=-11

-x=-11+16

-x=5

x=-5

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lapo4ka [179]

Answer:

RX = 12 and XU = 6

Step-by-step explanation:

Given :  In ΔTRV , TW ,RU and VS are the medians .

             X is the centroid

To Find : RX and XU

Solution:

Since we know that the centroid divides each median in a ratio of 2:1.



Since X is the centroid so RX : XU = 2:1

So, let RX = 2x and XU = x

And we are given that RU = 18

⇒RX +XU=18

⇒2x+x=18

⇒3x=18

⇒x=\frac{18}{3}

⇒x=6

Thus,  RX = 2x = 2*6 =12

          XU = x =6

Hence length of RX = 12 and XU = 6

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3 years ago
Mackenzie earns 4% commission as a salesperson. She sold a digital camera that cost $767. How much commission did Mackenzie earn
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Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript one-fourth x?
Nat2105 [25]
<h3>Answer: Choice C</h3>

RootIndex 12 StartRoot 8 EndRoot Superscript x

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\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}

=========================================

Explanation:

The general rule is

\sqrt[n]{x} = x^{1/n}

so any nth root is the same as having a fractional exponent 1/n.

Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)

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-----

Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so

(1/3)*(1/4)x = (1/12)x

In other words,

\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/3)*(1/4)x}

\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/12)x}

-----

From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this

8^{(1/12)x} = \sqrt[12]{8^{x}}

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4 0
2 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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