Answer:
RX = 12 and XU = 6
Step-by-step explanation:
Given : In ΔTRV , TW ,RU and VS are the medians .
X is the centroid
To Find : RX and XU
Solution:
Since we know that the centroid divides each median in a ratio of 2:1.
Since X is the centroid so RX : XU = 2:1
So, let RX = 2x and XU = x
And we are given that RU = 18
⇒RX +XU=18
⇒2x+x=18
⇒3x=18
⇒
⇒
Thus, RX = 2x = 2*6 =12
XU = x =6
Hence length of RX = 12 and XU = 6
Answer:
like about $500 and because of the ca!erlsn
<h3>Answer: Choice C</h3>
RootIndex 12 StartRoot 8 EndRoot Superscript x
12th root of 8^x = (12th root of 8)^x
![\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D)
=========================================
Explanation:
The general rule is
![\sqrt[n]{x} = x^{1/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B1%2Fn%7D)
so any nth root is the same as having a fractional exponent 1/n.
Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)
![\sqrt[3]{8} = 8^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%208%5E%7B1%2F3%7D)
-----
Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so
(1/3)*(1/4)x = (1/12)x
In other words,


-----
From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this
![8^{(1/12)x} = \sqrt[12]{8^{x}}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20)
![8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D%20)
Answer:
Option (B)
Step-by-step explanation:

By applying multiplication property of the matrices,
Therefore, system of equations formed will be,
5x + 2y + z = 16
7x - 5y + 2z = 3
-5x + 3y + z = 12
Option (B) will be the correct option.
Answer:
17
Step-by-step explanation: