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Fantom [35]
3 years ago
15

A cylinder with radius 6 cm and height h cm has the same volume as a sphere with radius 4.5cm

Mathematics
1 answer:
lesya [120]3 years ago
7 0

Answer:

h = 4.22 cm

Step-by-step explanation:

Mathematically, we have the volume of a cylinder as;

V = pie * r^2 * h

We have it that the radius is 6 cm

V = pie * 6^2 * h

for the sphere, we have it that;

V = 4/3 * pie * r^3

V = 4/3 * pie * 4.5^3

We can proceed to equate both volumes;

pie * 6^2 * h = 5/3 * pie * 4.5^3

pie on both sides cancel out

6^2h = 5/3 * 4.5^3

36h = 151.875

h = 151.875/36

h = 4.22 cm

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On a particular game show, there are 8 covered buckets and 2 of them contain a ball.
kobusy [5.1K]

Answer:

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Step-by-step explanation:

The buckets are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

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C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

8 covered buckets, so N = 8.

4 buckets are selected, so n = 4.

2 contain a ball, which means that k = 2.

Find the probability that a contestant wins the game if he/she gets to select 4 of the buckets.

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,8,4,2) = \frac{C_{2,2}*C_{6,2}}{C_{8,2}} = 0.2143

0.2143 = 21.43% probability that a contestant wins the game if he/she gets to select 4 of the buckets.

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3 years ago
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68.48

100% divided by 6.25% is 16 columns
Second row is 4.28 each
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