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KATRIN_1 [288]
3 years ago
13

Select ALL solutions for this equation: 2 + 2 = x - 10

Mathematics
1 answer:
aalyn [17]3 years ago
4 0

Answer:

x = 14

Step-by-step explanation:

4 = x - 10

-x = -10 -4

-x = -14

Therefore; x = 14

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What is the length of the arc intercepted by an angle of 10 degrees on a circle with a radius of 10 meters?
soldier1979 [14.2K]
   
\displaystyle\\
\texttt{Length of the arc }= 2\pi R\times  \frac{10}{360} = \frac{2\pi \times 10}{36} = \frac{20\pi}{36} =  \boxed{\frac{5\pi}{9}~m}



3 0
3 years ago
2x-4/5=4<br> plsss answer quick
nikdorinn [45]

Answer:

<h2>x = 12</h2>

Step-by-step explanation:

\frac{2x - 4}{5}  =4

First of all multiply through by 5 to eliminate the fraction

That's

5 \times  \frac{2x - 4}{5}  = 4 \times 5 \\ 2x - 4 = 20

Next using the addition property add 4 to both sides of the equation

We have

2x - 4 + 4 = 20 + 4 \\ 2x = 24

<u>Divide both sides by 2</u>

\frac{2x}{2}  =  \frac{24}{2}

We have the final answer as

<h3>x = 12</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
What is the circumference of a circle with a diameter of 7 inches? (use for pi)
Marrrta [24]

Answer:

21.9

Step-by-step explanation:

circumference = pi x diameter

3.14 x 7 = 21.9

3 0
4 years ago
Read 2 more answers
Find the circumference of the circle in terms of π.
SSSSS [86.1K]

Answer:

  • C) 12π cm

Step-by-step explanation:

<u>Circumference formula:</u>

  • C = 2πr

Given r = 6 cm

<u>Circumference is:</u>

  • C = 2π*6 cm = 12π cm

Correct choice is C

4 0
3 years ago
How would you solve these 2 maths problems?
sweet-ann [11.9K]

Answer:

see explanation

Step-by-step explanation:

(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

compare with

x³ + 2x² - 3x + 4

x² terms

a - 2 = 2 ( add 2 to both sides )

a = 4

x terms

b - 2a = - 3 ← substitute a = 4

b - 8 = - 3 ( add 8 to both sides )

b = 5

constant terms

- 2b + c = 4 ← substitute b = 5

- 10 + c = 4 ( add 10 to both sides )

c = 14

Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = (-2)^{4} + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

- 8a + 4b + 56 = 0

- 8a + 4b = - 56 → (1)

and

g(- 2) = (-2)^{4} + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

b = - 28

Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

5 0
3 years ago
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