Answer:

Step-by-step explanation:
Values less than 5 on a die are 1, 2, 3, 4 ← 4 values out of a possible 6
P( < 5) =
=
in simplest form
Answer:
it's either 32 or 16f I don't know though
2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>