Looks like the system is
We can eliminate 
by taking
so that 
, and
Substitute into this last equation and solve for 
:
Then
Plug these values into any one of the original equation to solve for :
Hence the solution is x = 4, y = -3, and z = 2.
The length of the line segment here is 13.
Distance Formula:
√((x₂ - x₁)² + (y₂ - y₁))
√((5 - 0)² + (0 - 12)²) = 13
I thinks 5 because -2(x) = -2x and -2(5)=-10
So -2x=-10
-10/-2=5
X=5
The Answer is b: x = 18, y = -20
Proof:
Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{7 x + 5 y = 26 | (equation 2)
Swap equation 1 with equation 2:
{7 x + 5 y = 26 | (equation 1)
{4 x + 3 y = 12 | (equation 2)
Subtract 4/7 × (equation 1) from equation 2:
{7 x + 5 y = 26 | (equation 1)
{0 x+y/7 = (-20)/7 | (equation 2)
Multiply equation 2 by 7:
{7 x + 5 y = 26 | (equation 1)
{0 x+y = -20 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{7 x+0 y = 126 | (equation 1)
{0 x+y = -20 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 18 | (equation 1)
{0 x+y = -20 | (equation 2)
Collect results:
Answer: {x = 18, y = -20
