Given f (x) = 2x^2 -3x + 5, find f (-4)

Mathematics

2 answers:

Liono4ka [1.6K]2 years ago

6 0

Below is my answer :)

bogdanovich [222]2 years ago

4 0

-1=x is the answer I’m pretty sure

You might be interested in

A walking path across a park is represented by the equation Y equals negative 2X -7. A new path will be built perpendicular to t

Ulleksa [173]

So we are given an initial equation of: $y=2x-7$ .

We are told that a new path is going to be perpendicular to this line. So to find a slope that is perpendicular to a line, we take the slope of the known line (in this case 2) and we flip it and change the sign. So since this slope is essentially $\frac{2}{1}$ , we are going to flip it to make it $\frac{1}{2}$ and change the sign to make it $-\frac{1}{2}$ .

So now we know that the slope of the perpendicular line is $-\frac{1}{2}$ , we can start a new equation for this line:

$y=-\frac{1}{2}x+b$

We are also told that the path will intersect at (-2,-3) - this is a solution to the two lines. So to find b in this new equation, let's plug in the x and y values found in the point:

$-3=-\frac{1}{2}(-2)+b$

Then solve for b:

$-3=1+b$

$b=-4$

So then we plug in our value for b and leave x and y:

$y=-\frac{1}{2}x-4$

So this equation now represents the new path.

3 0

3 years ago

A wallet contains five $10 bills, three $5 bills, six $1 bills, and no larger denominations. If bills are randomly selected one-

Black_prince [1.1K]

Answer:

$\frac{4}{21}$

Step-by-step explanation:

Another way of phrasing this question is this; if only two bills are selected without replacement, what is the probability that at one of the two bills will be a $10 bill:

P(One $10 bill) = P(picking a $10 bill first then another type) + (picking another

type then a $10 bill)

= $\frac{5}{15}*\frac{10}{14}+\frac{10}{15} *\frac{5}{14} = \frac{4}{21}$