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Alina [70]
3 years ago
11

What's one-sixth of 1/2

Mathematics
2 answers:
lys-0071 [83]3 years ago
8 0
Answer:

1/12

Hope this helps!
Ganezh [65]3 years ago
4 0
1/12

That is the answer
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Please help me I’m begging you :)
Nataly_w [17]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
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Find the reference angle for 105 degree angle.
m_a_m_a [10]

Answer:

75° degree angle

Step-by-step explanation:

Since the angle 105° is in the second quadrant, subtract 105° from 180° .

180-105=75

6 0
3 years ago
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Robert is traveling to Mexico for a family vacation. He is bringing 625 U.S. dollars with him. Robert needs to exchange his mone
Evgesh-ka [11]

Robert should get D. 8281.25 pesos in exchange.

Explanation:

  • Robert is bringing 625 U.S. dollars with him to Mexico. He needs to exchange the money he has with him to Mexico's currency i.e. from U.S. dollars to Mexican pesos.
  • The exchange rate is 13.25 Mexican pesos for each U.S. dollar. So                               1 U.S. dollar = 13.25 Mexican pesos.
  • So to calculate how much 625 U.S. dollars is in pesos we multiply 625 with the exchange rate i.e. 13.25 pesos                                                        625 U.S dollars = 625 × 13.25 = 8281.25 Mexican pesos.

7 0
3 years ago
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

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3 years ago
Nick made an array that has 10 counters. Draw 4 arrays that he might have made
ELEN [110]
You could draw a 2•5 5•2 10•1 and 1•10
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4 years ago
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