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posledela
2 years ago
15

Can I get help with this?

Mathematics
1 answer:
tankabanditka [31]2 years ago
5 0

Answer:

x = 23

Step-by-step explanation:

Use tan to find the missing side

tan 41 = 20/x     SImplify

0.8693 = 20/x   Multiply both sides by x

0.8693x = 20    Divide both sides by 0.8693

x = 23

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How to make a mixed number a improper fraction ​
Elena L [17]

A mixed number of the form a\frac{b}{c} can be turned into an improper fraction by using the fact that a mixed number is really het whole number plus its fraction part, so

  a\frac{b}{c} = {\displaystyle a + \frac{b}{c}=\frac{a}{1}+\frac{b}{c}}

Then do the usual procedure for adding fractions via common denominator.

For example, to convert the mixed number 5 \frac{1}{4} into an improper fraction, we have

  5\frac{1}{4}={\displaystyle 5 +\frac{1}{4}=\frac{5}{1}+\frac{1}{4}}

To add \frac{5}{1}+\frac{1}{4}, we need \frac{5}{1} to have a denominator of 4, so we multiply the numerator and denominator by 4 to get

   =\frac{5\cdot 4}{1 \cdot 4}+\frac{1}{4}=\frac{20}{4}+\frac{1}{4} = \frac{21}{4}

Therefore,

  5\frac{1}{4} = \frac{21}{4}

6 0
3 years ago
Triangle ABC was transformed using the rule (x, y) → (–y, x). The vertices of the triangles are shown. A (–1, 1) B (1, 1) C (1,
yaroslaw [1]

Answer:

the transformation was 90° at the origin

Step-by-step explanation:

the transformation was 90° at the origin

5 0
3 years ago
Read 2 more answers
Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
What is 37 1/4 x 24 help me
-BARSIC- [3]

37 and 1 / 4 = 37 * 6 = 74 * 3 = 222

5 0
2 years ago
I need the answer please
Yuri [45]

Answer:

D - All rational numbers are integers.

Step-by-step explanation:

This is because integers is a subcategory of rational numbers, so there are other rational numbers that aren't integers.

3 0
3 years ago
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