A line passes through the points (1, 2) and (4, 4). What is the slope of the line?

A publisher reports that 63c% of their readers own a personal computer. A marketing executive wants to test the claim that the p

rusak2 [61]

Answer:

Null hypothesis is not rejecting at 0.05 level.

Step-by-step explanation:

We are given that a publisher reports that 63% of their readers own a personal computer. A random sample of 110 found that 56% of the readers owned a personal computer.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, $H_0$ : p = 0.63 {means that the percentage of readers who own a personal computer is same as reported 63%}

Alternate Hypothesis, $H_1$ : p $\neq$ 0.63 {means that the percentage of readers who own a personal computer is different from the reported 63%}

The test statistics we will use here is;

T.S. = $\frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }$ ~ N(0,1)

where, p = actual % of readers who own a personal computer = 0.63

$\hat p$ = percentage of readers who own a personal computer in a

sample of 110 = 0.56

n = sample size = 110

So, Test statistics = $\frac{0.56 -0.63}{\sqrt{\frac{0.56(1- 0.56)}{110} } }$

= -1.48

Now, at 0.05 significance level, the z table gives critical value of -1.96 to 1.96. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, null hypothesis is not rejecting at 0.05 level.

3 0

2 years ago

Does anyone know answers?

Lady bird [3.3K]

2x is 90 by 32 # the answer is such

6 0

3 years ago

Read 2 more answers

What are the slope and x and y intercept of 3x-6y=18? <br><br><br> please help me

amid [387]

X intercept (6,0)
y intercept (-3,0)
slope is m= 1/2

3 0

3 years ago

If f(x) = 2x2 - 5 and g(x) = 3x + 3, find (f - g)(x).

Vera_Pavlovna [14]

Answer: A. 2x2 - 3x - 8

Just subtract the functions and combine like terms
(f - g)(x) = f(x) - g(x)
(f - g)(x) = 2x^2 - 5 -(3x + 3)
(f - g)(x) = 2x^2 - 5 - 3x - 3
(f - g)(x) = 2x^2 - 3x - 8

7 0

2 years ago

A model for the population in a small community after t years is given by P(t)=P0e^kt.

LUCKY_DIMON [66]

$\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}$

a)

so, if the population doubled in 5 years, that means t = 5. So say, if we use an amount for "i" or P in your case, to be 1, then after 5 years it'd be 2, and thus i = 1 and A = 2, let's find "r" or "k" in your equation.

$\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &2\\
I=\textit{initial amount}\to &1\\
r=rate\\
t=\textit{elapsed time}\to &5\\
\end{cases}
\\\\\\
2=1\cdot e^{5r}\implies 2=e^{5r}\implies ln(2)=ln(e^{5r})\implies ln(2)=5r
\\\\\\
\boxed{\cfrac{ln(2)}{5}=r}\qquad therefore\qquad \boxed{A=e^{\frac{ln(2)}{5}\cdot t}} \\\\\\
\textit{how long to tripling?}\quad 
\begin{cases}
A=3\\
I=1
\end{cases}\implies 3=1\cdot e^{\frac{ln(2)}{5}\cdot t}$

$\bf 3=e^{\frac{ln(2)}{5}\cdot t}\implies ln(3)=ln\left( e^{\frac{ln(2)}{5}\cdot t} \right)\implies ln(3)=\cfrac{ln(2)}{5} t
\\\\\\
\cfrac{5ln(3)}{ln(2)}=t\implies 7.9\approx t$

b)

A = 10,000, t = 3

$\bf \begin{cases}
A=10000\\
t=3
\end{cases}\implies 10000=Ie^{\frac{ln(2)}{5}\cdot 3}\implies \cfrac{10000}{e^{\frac{3ln(2)}{5}}}=I
\\\\\\
6597.53955 \approx I$

3 0

3 years ago