I hope this helps you
x^2=50
x= 5 square root of 2
Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
Answer:
C
Step-by-step explanation:
Its not A because The left side 6 is not less than the right side 5, which means that the given statement is false.
Its not B because The left side 6 is not less than the right side 5, which means that the given statement is false.
Its C because The left side 5 is less than the right side 6, which means that the given statement is always true.
Its not D because The left side is 5 is not less than the right side 6, which means that the given statement is false.
