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pshichka [43]
3 years ago
14

Helppp u will get point ASAP

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

Answer: 10 degrees

Step-by-step explanation:

Since it is a right triangle the angle is 90 degrees.

So, 90 degrees -50 degrees is equal to 40 degrees.

40 divided by 4 is 10.

So your answer is 10 degrees.

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(5n)2 and 5n? are equivalent expressions.<br> a<br> true<br> b<br> false
Talja [164]

Answer:

b false

Step-by-step explanation:

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3 years ago
Consider the quadratic function.
Genrish500 [490]
Mark Brainliest please

Answer :

a = 1, b = -8, c = -5

Explanation

A standard form for the quadratic function is f(x) = ax2 + bx + c where the coefficients are a, b, and c.
The given quadratic function is f(p) = P2 - 8P - 5 When this function is compared to the standard form, with p replacing x, we obtain a = 1 because the leading term is 1*p2, b = -8 because the linear term is -8*p, c = -5 because the constant term is -5.
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6 0
3 years ago
Find the area of the region bounded by the graphs of y = x, y = −x + 4, and y = 0.
Marrrta [24]
The line y = x and y = -x + 4 intersect when at the point (2, 2).

Expresing y = -x + 4 in terms of x, we have x = 4 - y.

Thus, the area of the region bounded by the <span>graphs of y = x, y = −x + 4, and y = 0 is given by

\int\limits^2_0 {(y-(4-y))} \, dy = \int\limits^2_0 {(y-4+y)} \, dy \\  \\ = \int\limits^2_0 {(2y-4)} \, dy= \left[y^2-4y\right]_0^2 =|(2)^2-4(2)| \\  \\ =|4-8|=|-4|=4

Therefore, the area bounded by the lines is 4 square units.
</span>
4 0
3 years ago
Convert r=sec thaeta to rectangular form
Maslowich
Multiply both sides by <span>cos</span><span>
</span><span>r<span>cos<span>(θ)</span></span>=<span>sec<span>(θ)</span></span><span>cos<span>(θ)</span></span>=1</span><span>
</span><span>x=r<span>cos<span>(θ)</span></span></span><span>
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3 0
4 years ago
A rectagular, above ground pool is 18 feet long, 9 feet wide, and 54 inches deep. One cubic foot of water weighs about 62.4 poun
ollegr [7]

Answer:

45,489.6 pounds!

Step-by-step explanation:

To solve this problem, first we need to find the volume of the pool.

We know that the dimensions of the pool are:

Width = 9ft

Length = 18ft

Height = 54in = 4.5 ft

So the volume of the pool is:

Volume = Width x Length x Height = 9ftx18ftx4.5ft = 729ft^3

We know that one cubic foot of water weights about 62.4 pounds. To fill the  pool, we will need 729ft^3 of water.

So the weight of the water is:

Weight = 729ft^3 x 62.4 pounds/ft = 45,489.6 pounds!

4 0
3 years ago
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