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2 years ago

6

091 rounded to hundreths place

1 answer:

Zina [86]2 years ago

4 0

There has to be a decimal in order to round to the "hundreths" place. I'm assuming you meant ".091" in which case you would look at the hundreths column, which is a 9. Then to round, you look at the number to the right of the number you're rounding, if it's greater than 5 you round up, less than 5 you stay the same. Since the number to the right is 1, your final answer is ".09"

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3 years ago

QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

<u>Part A </u>

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

<u>Part B </u>

<u>(Fixed Cost)</u>

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

<u> Marginal Cost Function</u>

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

<u>Part C </u>

<u>Profit Function </u>

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

<u> Part D </u>

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

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3 years ago

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2 years ago

Read 2 more answers

If my original price is $60, then the sale price is $45, what is the percent discount

Scorpion4ik [409]

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The percent discount is 25%~

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