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notka56 [123]
3 years ago
14

Given, y = x2 – 6x + 8, algebraically determine the axis of symmetry.

Mathematics
1 answer:
Nitella [24]3 years ago
8 0

Answer: 3

Step-by-step explanation:

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Can anyone help me out with these before 10:00 I’d greatly appreciate it ty!! :)
patriot [66]

Answer:

The question and many

I will give you a tip

Use the formulary they use for calculating angle on a straight line that is 180 and angle at a point

4 0
2 years ago
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Solve the formula for the variable y: 5x+2y=10
Inessa05 [86]

The process is to go step-by-step to isolate the y.

To do this, you basically run the order of operations in reverse.

In 5x+2y=10, the first thing to move away from the left side is 5x and  you cancel it out by subtracting 5x from both sides:

    5x+2y - 5x = 10 - 5x

The 5x's on the left cancel leaving you with:  

   2y = 10 - 5x

Side note: this is more commonly written as 2y = -5x+10, since we tend to write variable terms first.

Finally, to get the y fully by itself, you need to cancel the 2 that's multplied against it.  To cancel multiplication, you need to divide:

    \dfrac{2y}{2} = \dfrac{-5x+10}{2}

The most important thing to remember here is that the 2 needs to divide into both terms on the right:

    \dfrac{2y}{2} = \dfrac{-5x}{2}+ \dfrac{10}{2}

Finally, we simplify this into:

    y = -\dfrac{5}{2}x+5

5 0
3 years ago
Help <br> Fjdjdjdjdjdjdjdjdjjd
trasher [3.6K]

Answer:

D. -2/5

Step-by-step explanation:

6 0
3 years ago
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Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
Practice
viva [34]

Answer:

B.

Step-by-step explanation:

x = small box

(small box + 5 ounces) = large box.

B shows:

x + (x + 5) = 27

Small box + (small box + 5 ounces) = 27 ounces.

Small box + large box = 27 ounces.

————————————————————

Why A and C are incorrect.

A describes:

x + 5x = 27

Small box + 5 multiplied by small box = 27

(5 multiplied by small box is equivalent to 5 small boxes.)

Small box + 5 small boxes = 27

C describes:

x + 5 = 27

small box + 5 ounces = 27

Large box = 27

(We know that a small box + 5 ounces is a large box)

7 0
3 years ago
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