Answer:
The equation of your line is y=1x+2
Step-by-step explanation:
first you take y2-y1/x2-x1
y2=-1 y1=5
x2= -3 x1= 3
that gives you your slope so (-1-5)/ (-3-3) = 1
y=mx+b
mx is your slope
y=1x+b
to solve for b you input your slope and one of your points (I used (3,5)
5=1(3) +b
solve for b and you get 2
then put your mx and b into the equation of a line
y=1x+2
and thats your answer
You can also check your work by using a graphing calculator and checking that the line goes through those two points.
It will be charged 5 times
The quadratic formula is x=(-b+-sqrt(b^2-4(a)(c)))/2a
Using the quadratic formula, we get:
x=(-(-8)+-sqrt((-8)^2-4(15)(1)))/2(1)
x=(8+-sqrt(64-60))/2
x=(8+-sqrt(4))/2
x=(8+-2)/2
x=10/2 and x=6/2
x=5 and x=3
We could do it way faster by completing the square:
x^2-8x+15=0
(x-5)(x-3)=0
x=5 and x=3
Hope both methods make sense! BTW, the +- thing means add or subtract
Answer:
20 bucks
Step-by-step explanation:
50 - 20 = 30 which then means she gets 30 bucks back
The key feature of the functions that are needed to determine if the lines intersect are;
- The slope; rate of change
- The y-intercept
<h2>
Slope and y-intercept</h2>
From straight line geometry, we can conclude that two parallel lines whose slope are equal can never intersect.
On this note, for the functions described in the question, the functions only intersect when the slopes are different.
Additionally, the functions may intersect in the event of having equal y-intercepts.
In order two straight lines in a coordinate plane intersect, they MUST have different slopes.
This condition is NECESSARY and SUFFICIENT.
