Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
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Answer:
yo answer woud be b √5/4
Step-by-step explanation:
Answer: 32.52
Step-by-step explanation :if I’m correct this is supposed to be a decimal ( here we use the dot not the comma ) but if so then 32.52 a good way to remember is 5 or more let it sore (meaning round up) four or less let it rest (meaning it stays the same)
Answer:
3sqrt2
Step-by-step explanation:
If a side length is a, then a^2 + a^2 = 36
2a^2 = 36
a^2 = 18
a = 3sqrt2
Or, you can remember that in a square, if you cut it in half diagonally, you get a 45-45-90 triangle, so the sidenglth is diagonal/sqrt2
