Question

The area of a rectangle is 72cm2, in which the width is twice the length. what are the dimensions

Answer 1

Answer:

Dimension: 2inches by 4 inches

Step-by-step explanation:

Given

$Width = 2wice\ Length$

Required

Determine the dimension.

This is calculated as :

$Area = Length * Width$

$A = L * W$

So:

$A=L * 2L$

$A=2L^2$

Substitute 72 for A

$72=2L^2$

Divide bith sodes by 2

$36 = L^2$

Take square root of both sides

$L = 6$

Recall that:

$Width = 2 * Length$

Hence:

$LEnhth= 0 * 2$

$LEnhth= 2$

Hence, the dimension is: 2 by 3 inches