Answer:
The first one to your left
Step-by-step explanation:
Y=1/x is a reciprocal function & its shape is a special hyperbola with one branch located in the 1st Quadrant and the second in the 3dr Quadrant and both are symmetric about the origin O.
If a> 1 → y=a/x and the 2 branches are equally stretched upward & downward
about the center O.
If 0 < a < 1→y =a/x, the 2 branches are equally stretched downward and upward about the center O.
If a<0, then the 2 legs are in the 2nd and 4th Quadrant respectively
Answer:
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
Step-by-step explanation:
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
Coordinate of A are (0,0)
Coordinates of A' are (5,2)
We can find the distance from A to A' using the distance formula:
Thus, rounded to nearest hundredth, AA' is equal to 5.39
Infinite sets may be countable or uncountable. Some examples are: the set of all integers, {..., -1, 0, 1, 2, ...}, is a countably infinite set; and. the set of all real numbers is an uncountably infinite set.
