<span>The first ionization
energy is the energy that is obligatory in order to eliminate the first
electron from an atom(neutral) in the GAS phase
, the second ionization energy is defined as the
energy required to remove the second electron from an atom(+1 ion) in the GAS phase.
</span>the third ionization energy is the energy it takes to remove an electron from a 2+ ion. (That means that the atom has already lost two electrons, you are now removing the third.)
<span> Ionization energy will normally increase for every electron that is removed and
increases from left to right in the periodic table and moving up the periods
hope it helps</span>
80 minutes because:
1600 -> 20mins -> 800
800 -> 20 mins -> 400
400 -> 20 mins -> 200
200 -> 20 mins -> 100
4*20 mins = 80 minutes
The grams of the sugar in 125 g of the drink is calculated as below
%M/m) = mass of the solute (sugar)/ mass of the solvent(drink) x100
let the mass of the solute(sugar) be represented by y
convert % into fraction by dividing by 100 = 10.5/100
10.5/100 = y/125
by cross multiplication
100y =1312.5
divide both side by 100
y=13.125 grams
Answer:
1: f 2: b 3: d 4: e 5:a 6:c
Explanation:
Answer:
20.95 g of caffeine, C₈H₁₀N₄O₂
Explanation:
From the question given above, the following data were obtained:
Number of molecules of C₈H₁₀N₄O₂ = 6.5×10²² molecules
Mass of C₈H₁₀N₄O₂ =?
From Avogadro's hypothesis,
1 mole of C₈H₁₀N₄O₂ = 6.02×10²³ molecules
Next, we shall determine the mass of 1 mole of C₈H₁₀N₄O₂. This can be obtained as follow:
1 mole of C₈H₁₀N₄O₂ = (8×12) + (10×1) + (4×14) + (2×16)
= 96 + 10 + 56 + 32
1 mole of C₈H₁₀N₄O₂ = 194 g
Thus,
194 g of C₈H₁₀N₄O₂ = 6.02×10²³ molecules
Finally, we shall determine the mass of caffeine, C₈H₁₀N₄O₂ that contains 6.5×10²² molecules. This can be obtained as follow:
6.02×10²³ molecules = 194 g of C₈H₁₀N₄O₂
Therefore,
6.5×10²² molecules = (6.5×10²² × 194) / 6.02×10²³
6.5×10²² molecules = 20.95 g of C₈H₁₀N₄O₂.
Therefore, 20.95 g of caffeine, C₈H₁₀N₄O₂ contains 6.5×10²² molecules
