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A reaction in which Oxygen (O₂) is produced from Mercury Oxide (HgO) would be a decomposition reaction.
2HgO → 2Hg + O₂
If 250g of O₂ is needed to be produced,
then the moles of oxygen needed to be produced = 250g ÷ 32 g/mol
= 7.8125 mol
Now, the mole ratio of Oxygen to Mercury Oxide is 1 : 2
∴ if the moles of oxygen = 7.8125 mol
then the moles of mercury oxide = 7.8125 mol × 2
= 15.625 mol
Thus the number moles of HgO needed to produce 250.0 g of O₂ is 15.625 mol
Methane is lighter than air, having a specific gravity of 0.554. It is only slightly soluble in water. It burns readily in air, forming carbon dioxide
and water vapour; the flame is pale, slightly luminous, and very hot.
The boiling point of methane is −162 °C (−259.6 °F) and the melting
point is −182.5 °C (−296.5 °F). Methane in general is very stable, but
mixtures of methane and air, with the methane content between 5 and 14
percent by volume, are explosive. Explosions of such mixtures have been
frequent in coal mines and collieries and have been the cause of many
mine disasters.
Answer:
0.013 moles Cl
Explanation:
Grams --> Moles Divide by Molar Mass
Molar Mass of Chlorine (Cl) is 35.5. This can be found on the Periodic Table.
Set Up: (0.456 g Cl) (1 Cl / 35.5 g)
0.456 g * 1 = 0.456
0.456 / 35.5 = 0.01284507
Round to 0.013
Answer:
10 °C
Explanation:
Hello,
Based on the atmospheric conditions, unsaturated air cools at a constant rate of 10 °C per 1000 meters of ascent, meanwhile saturated air cools at a slower rate above the lifting condensation level due to the release of latent heat for the wet adiabatic rate.
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