Find the least common multiple of 12 and 18?

Help me with this 1,2,3. For each sequence, Determine with whether it appears to be arithmetic If it does find a common differen

pshichka [43]

Problem 1

<h3>Answer: Arithmetic, common difference = -4</h3>

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Explanation:

Pick any term of the sequence, and subtract off the previous term to find that,

term2 - term1 = -12 - (-8) = -12 + 8 = -4
term3 - term2 = -16 - (-12) = -16 + 12 = -4
term4 - term3 = -20 - (-16) = -20 + 16 = -4

Each time we get the same result, so that means we have an arithmetic sequence with common difference -4

This indicates that adding -4 to each term, or subtracting 4 from each term, will generate the next one.

Eg: term2 = term1 - 4 = -8-4 = -12.

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Problem 2

<h3>Answer: Arithmetic, common difference = 5</h3>

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Explanation:

Similar to problem 1, this sequence is also arithmetic because we add on 5 to each term to get the next one

-6+5 = -1
-1+5 = 4
4+5 = 9

Or you could subtract adjacent terms as done in problem 1, to find that the common difference is 5.

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Problem 3

<h3>Answer: Not arithmetic</h3>

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Explanation:

Unlike the previous two problems, this sequence is not arithmetic.

We can see that

term2 - term1 = 12 - 3 = 9
term3 - term2 = 48 - 12 = 36

The gaps of 9 and 36 aren't the same. We need the same common difference between any adjacent terms to have an arithmetic sequence.

This sequence is instead geometric because

term2/term1 = 12/3 = 4
term3/term2 = 48/12 = 4
term4/term3 = 192/48 = 4

Each quotient is 4, showing the common ratio is 4. To find the next term, we multiply the current term by 4. So the next term after 192 would be 4*192 = 768, then 4*768 = 3072 is next, and so on.

3 0

3 years ago

Jen’s goal is to run a total of 22 miles in five days. The table below shows her log for the number of miles she ran on Monday,

Ronch [10]

Answer: 5.875 miles run on Friday to reach her goal by Jen

Step-by-step explanation:

Since we have given that

Part of distance covered on Monday by Jen is given by

$4\frac{3}{4}=\frac{19}{4}$

Part of distance covered on Tuesday by Jen is given by

$5\frac{1}{8}\\\\=\frac{41}{8}$

Part of distance covered on Wednesday by Jen is given by

0

Part of distance covered on Thursday by Jen is given by

$6\frac{1}{4}\\\\=\frac{25}{4}$

Total part of distance covered in these four days by Jen is given by

$\frac{19}{4}+\frac{41}{8}+0+\frac{25}{4}\\\\=\frac{38+41+0+50}{8}\\\\=\frac{129}{8}=16.125\ miles$

Remaining part of distance will be covered on Friday to reach her goal which is given by

$22-16.125=5.875\ miles$

Hence, 5.875 miles run on Friday to reach her goal by Jen.

5 0

3 years ago

Read 2 more answers

Consider the line y=9x-1.

OLEGan [10]

Step-by-step explanation:

Slope=9

i)

$y−y1=m(x−x1)$

When line is parallel

y+5=9(x-6)

y+5 = 9x - 54

When line is perpendicular

y+5=-1/9(x-6)

9(y+5)= -1(x-6)

9y + 45 = -x+6

<h2>MARK ME AS BRAINLIST </h2>

5 0

2 years ago

What is the total weight of 7 penciles

Mamont248 [21]

Answer:

0.2 - 0.3 pounds

Step-by-step explanation:

Well because I dont know much information about the weight and background of the pencils. My answer may not be correct. But the average weight would be around 0.2 - 0.3 lbs.

6 0

3 years ago

Answer with steps please i have 1 mark on this with steps

Aleks04 [339]

Answer:

56cm²

Explanation:

the amount of material he needs would be the total surface area of the box. surface area can be calculated by finding the sum of surface area of all the sides of the box. since the opposite sides are equal, we can find the surface area of 3 different sides and then multiply it by 2.

(4 + 4) + (4 + 6) + (6 + 4) × 2

= 8 + 10 + 10 × 2

= 28 × 2

= <u>56cm²</u>

i hope this helps! :D

8 0

3 years ago