Find the value of X

A person invests $2,740 in an account that earns 4.3% annual interest. Find when the value of the investment reaches $7,000. If

Juli2301 [7.4K]

So, to set up your equation is the hardest part. If you remember the basic format, you're set.

I(t) = P * (1+r%)^t

t= time and this will be our variable

Initial amount P = $2740

Rate = 4.3% which converts numerically into .043

I(t) = 7000

Before we get to find out how to find how many years it takes to get to $7000, set up the basic equation by plugging in what we know.

I(t) = $2740(1+4.3%)^t

I(t)=2740(1.043)^t

Now plug in for $7000 for I(t)

7000=2740(1.043)^t Divide both sides by 2740

7000/2740 = 2740/2740(1.043)^t

2.55474453=(1.043)^t

Now you can solve for t in two ways. You can either use the natural log or graph it on your graphing calculate and see when the two equations meet.

In your calculator you can set up:

ln(2.55474453)/ln(1.043) = t which is the method I prefer since it's much simpler

t=22.278528

but you can also graph it in your ti-84

with

y1=2.55474453

y2=(1.043)^x

and find where they intersect on the graph.

either way it'll be the same answer

3 0

3 years ago

Solve the system of equations. −5x−3y−9=0 4x−18y−54=0 y=? x=?

Darina [25.2K]

Answer:

Step-by-step explanation:

Eq. 1 ) −5x−3y−9=0

Eq. 2) 4x−18y−54=0

there are two routes to solve this, Substitution or elimination, I'll go for the 2nd one because I can see that the y values are a multiple of each other :)

6 *( −5x−3y−9=0 )

Eq. 3) -30x -18y =54

subtract Eq. 2 from Eq. 3 :)

-30x -18y =54

-( 4x−18y=54)

-34x = 0

so according to the equations then x =0 but, that's not really a full answer, so now we should go back and try the other method, substitution,

then:

-5x = 9 +3y

x = - 9/5 + (-3/5)y

now plug that into Eq. 2

4( - 9/5 + (-3/5)y ) - 18y = 54

-36/5 + (-12/5)y -18y = 54

(-12/5)y - (90/5)y = 54+36/5

-(102/5)*y =270/5+36/5

-(102/5)y = 306/5

y = (-5/102)*(306/5)

y = -306/102

y = -3

then plug in for either equation

-5x-3( -3) = 9

-5x + 9 = 9

-5x = 0

x = 0

now we have the full answer

check it by plugging in both x and y into the 2nd equation

4(0) - 18(-3) = 54

54= 54

this seems good

3 0

3 years ago

WILL GIVE BRAINLIEST!! What are the slope and the y-intercept of the linear function that is represented by the graph?

UNO [17]

Answer:

its d

Step-by-step explanation:

y=-3/4+3 I think that's right

3 0

3 years ago

Read 2 more answers

NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE

tia_tia [17]

Answer:

Q1:

$-5\sqrt{27c^2}$

$-5\sqrt{27}\sqrt{c^2}$

$-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}$

$-5\times3\sqrt{3}\sqrt{c^2}$

$-5\times3\sqrt{3}c$

$-15\sqrt{3}c$

Q2:

$5\sqrt{72}-3\sqrt{32}$

$5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}$

$5\times6\sqrt{2}-3\times4\sqrt{2}$

$30\sqrt{2}-12\sqrt{2}$

$18\sqrt{2}$

Q3:

$\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}$

$\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}$

$6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}$

$16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}$

Q4:

$\sqrt{15n^2}\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}$

$\sqrt{15}\sqrt{10}n^2\sqrt{n}$

$\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{3}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{6}n^2\sqrt{n}$

Q5:

$\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}$

$\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}$

Cancel off $\sqrt{x}$ :

$\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}$

Cancel off $y:$

$\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}$

Cancel off $\sqrt{y} :$

$\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}$

Multiply $\sqrt{5}$ on the numerator and denominator:

$\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}$

$\frac{\sqrt{15}\sqrt{x}}{20}$

5 0

3 years ago

A Chevy Malibu has a fuel capacity of 18.5 gallons. This vehicle averages 666 miles per tank. Assume the relationship between fu

Nuetrik [128]

Answer:

180 miles

Step-by-step explanation:

Step one:

capacity of tank= 18.5gallons

vehicle averages 666 miles per tank.

Hence, the vehicle can travel 666 miles on 18.5 gallons

Required

The distance covered on 5 gallons

Step two:

vehicle can travel 666 miles on 18.5 gallons

the vehicle will go x miles on 5 gallons

cross multiply we have

5*666= 18.5*x

3330=18.5x

divide both sides by 18.5

x= 3330/18.5

x=180 miles

5 0

3 years ago