Question

1/3y + 8/3y = 9/3y for y not = / / / (fraction over fraction over fraction) simplify the sum. State any restrictions on the variable

Answer 1

Answer:

$\frac{1}{3}y+\frac{8}{3}y=\frac{9}{3}y$

Step-by-step explanation:

As the given expression

$\frac{1}{3}y+\frac{8}{3}y=\frac{9}{3}y$

Simplifying the left side of the expression

$\frac{1}{3}y+\frac{8}{3}y$

$\mathrm{Factor\:out\:common\:term\:}y$

$=y\left(\frac{1}{3}+\frac{8}{3}\right).....A$

Solving

$\frac{1}{3}+\frac{8}{3}$

$\mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{1+8}{3}$

$\mathrm{Add\:the\:numbers:}\:1+8=9$

$=\frac{9}{3}$

so the equation A becomes

$=\frac{9}{3}y$

Therefore,

$\frac{1}{3}y+\frac{8}{3}y=\frac{9}{3}y$