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evablogger [386]
4 years ago
15

Consider the error in using the approximation e−x≈1−x on the interval [−1,1]. (a) reasoning informally, on what interval is this

approximation an overestimate? 1 an underestimate? (for each, give your answer as an interval or list of intervals,
e.g., to specify the intervals −0.25≤x<0.5 and 0.75
Mathematics
1 answer:
crimeas [40]4 years ago
6 0

e^{-x} \approx 1 - x

is a classic approximation, true for small x.

The next term in the polynomial expansion will be +kx^2 where k is a positive number. So our estimate 1-x is definitely an underestimate on both sides of x=0.

Since for negative xs the exponential rises exponentially and the line only linearly, the exponential exceeds the line for all negative x. For positive x, the line quickly goes negative while the exponential is always positive.

So, there's no interval for which our approximation is an overestimate.

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the value of "x" is 5 and the value of "y" is 12

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Round off 55.09 and 38.36 to the nearest tenth then add
Arte-miy333 [17]

Answer:

93.5

Step-by-step explanation:

0 and 3 are in the tenths place value

9 and 6 both increase when rounding

55.1 + 38.4 = 93.5

8 0
3 years ago
Denver is about 5,200 feet above sea level. Which number line best represents this integer?
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6 0
3 years ago
joe weighs 20lbs.less yhantwice jeffs weight.if jeff would gain 10lbs.,then together they wouldweigh 250lbs. how much does each
masya89 [10]
So,

Let x represent Joe's weight and y represent Jeff's weight.

"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250

We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250

Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250

We will use Elimination by Substitution.
2y - 20 + y + 10 = 250

Collect Like Terms.
3y - 10 = 250

Add 10 to both sides.
3y = 260

Divide both sides by 3.
Jeff's\ weight = 86 \frac{2}{3} \ lbs.

Substitute again.
x = 2(86 \frac{2}{3} )-20

Multiply.
x = 173 \frac{1}{3} -20

Subtract.
Joe's\ weight = 153 \frac{1}{3}\ lbs.

Check.

"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

Joe's\ weight\ is\ 153 \frac{1}{3} \ lbs.
Jeff's\ weight\ is\ 86 \frac{2}{3} \ lbs.
3 0
3 years ago
What is the solution set for x2+25=0
Masja [62]

Step-by-step explanation:

{x}^{2}  + 25 = 0 \\  \therefore {x}^{2}  =  - 25 \\ \therefore {x}  =  \sqrt{ - 25}  \\  \therefore {x}  =   \pm\sqrt{ - 1 \times 25}  \\ \therefore {x}  = \pm  \sqrt{  25}  \times  \sqrt{ - 1}  \\ \therefore {x}  =  \pm5 \: i  \\ \therefore {x}  = \{ - 5i, \:  \: 5i \} \: \\  is \: the \: solution \: set.

7 0
3 years ago
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