Question

Please answer this 2 question​

Answer 1

Answer:

Step-by-step explanation:

$2x^{99}+3x^{98}+2x^{97}+3x^{96}+.......+2x+3 = [2x^{99}+2x^{97}+...2x]+[3x^{98}+3x^{96}+......3]\\\\=2x*[x^{98}+x^{96}+...+1]+3[x^{98}+x{96}+....1]\\\\= [x^{98}+x^{96}+..+x^{2}.+1](2x+3)\\\\=( [x^{98}+x^{94}+...+x^{2}]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=(x^{2}*[x^{96}+x^{92}+.......+1]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=[x^{96}+x^{92}+.......+1](x^{2}+1)(2x+3)$