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3 years ago

Please answer this 2 question

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

$2x^{99}+3x^{98}+2x^{97}+3x^{96}+.......+2x+3 = [2x^{99}+2x^{97}+...2x]+[3x^{98}+3x^{96}+......3]\\\\=2x*[x^{98}+x^{96}+...+1]+3[x^{98}+x{96}+....1]\\\\= [x^{98}+x^{96}+..+x^{2}.+1](2x+3)\\\\=( [x^{98}+x^{94}+...+x^{2}]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=(x^{2}*[x^{96}+x^{92}+.......+1]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=[x^{96}+x^{92}+.......+1](x^{2}+1)(2x+3)$

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Help guys make p da subject of the formula

Basile [38]

Answer:

$p=\dfrac{m}{k-s}$

Step-by-step explanation:

When they ask you to make a variable the "subject of the formula", they're basically asking you to build a "machine" for it. In the expression $y=mx+b$ , for instance, if we know what m, x, and b are, we can plug them all in and out comes a value for y! To build that machine, we need to get it by itself on one side of the equation.

So, we want to build this machine for p, and the equation we have to build it out of is

$1=\dfrac{pk}{m+sp}$

One think we can immediately say about this equation: for a fraction to be equal to one, its numerator and denominator have to be equal to each other. So we can say

$m+sp=pk$

Ok, what next? Well, if we want p by itself, we need to somehow peel it off of that sp and pk. Let's collect them on the right side by subtracting sp from both sides:

$m=pk-sp$

p is a common factor of both sp and pk, so we can peel it away using the distributive property:

$m=p(k-s)$

And from here, we can divide both sides by $k-s$ and we'll have p as our subject:

$\dfrac{m}{k-s}=p$ or $p=\dfrac{m}{k-s}$

So if we know m, k, and s, we can easily solve for p. If m = 4, k = 2, and s = 0:

$p=\frac{4}{2-0} =\frac{4}{2}=2$

3 0

3 years ago

Explain why y = 3x IS an exponential function and y = x3 is NOT an exponential function.

arlik [135]

Because y=3x has a coefficient of 3 and y=x3 does not have a coefficient because the variable is the first terms. therefore it is not an exponential function.

8 0

2 years ago

What are the latitude and longitude coordinates of the entrance to the Mount Rushmore parking area?Latitude: 43.8753972, Longitu

Alborosie

Answer:

The answer is already in the question. The coordinates of the entrance to the Mount Rushmore parking area are given by latitude 43.8753972 and longitude -103.4523083.

Step-by-step explanation:

I believe the person asking the question wants some other detail that s/he did not state explicitly.

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3 years ago

Can some pls help me find the slope of this line i really really need help

Damm [24]

Answer:

Slope = Rise over Run

Rise = 2

Run = 3

Slope = 2/3

Let me know if this helps!

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3 years ago

A pack of 6 cans of pop costs £1.80. A pack of 10 cans of pop costs £3.50.

Lelechka [254]

Let us look at the cost per can of both packs.

Cost of can in 6-pack = 1.80/6

= £0.30

Cost of can in 10-pack = 3.50/10

= £0.35

Since the cost of a can in the 6-pack is cheaper, it would be better to buy the 6-pack if you were looking to save money.

5 0

3 years ago

Please answer this 2 question​

Please answer this 2 question