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Aleksandr-060686 [28]
3 years ago
10

Please answer this 2 question​

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0

Answer:

Step-by-step explanation:

2x^{99}+3x^{98}+2x^{97}+3x^{96}+.......+2x+3 = [2x^{99}+2x^{97}+...2x]+[3x^{98}+3x^{96}+......3]\\\\=2x*[x^{98}+x^{96}+...+1]+3[x^{98}+x{96}+....1]\\\\= [x^{98}+x^{96}+..+x^{2}.+1](2x+3)\\\\=( [x^{98}+x^{94}+...+x^{2}]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=(x^{2}*[x^{96}+x^{92}+.......+1]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=[x^{96}+x^{92}+.......+1](x^{2}+1)(2x+3)

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Kianna lives in a town where the streets are laid out in a grid. She uses a coordinate plane to draw a map of the town, with her
Dmitrij [34]

Answer:

1. The coordinates of Jo’s house are (-4,-2).

2. Kianna walks 8 blocks west, and 2 blocks south.

3. The coordinates of Elena’s house are (4,-2).

4. Kianna is incorrect.

Step-by-step explanation:

1. Since Jo’s house is reflected across both axes, we must reflect the coordinates two times. So we can reflect the coordinates of Kianna’s house across the x-axis first, which would give you the coordinates (4,-2). Then we reflect (4,-2) across the y axis, giving us the coordinates (-4,-2). So Jo’s house has the coordinates (-4,-2).

3. Since Elena’s house is only a reflection of Jo’s house across the x-axis only,  we can reflect Kianna’s house’s coordinates (4,2). When we reflect (4.2) over the x-axis, that gives us the coordinates (4,-2). So therefore Elena’s house has the coordinates (4,-2).

4. Kianna is incorrect, if Elena’s house was a reflection of her house across the y-axis, the coordinates would be (-4,2).

(A reflection can be thought of as folding or "flipping" an object over the line of reflection. The original object is called the pre-image, and the reflection is called the image.)

Hope this helps.

7 0
3 years ago
Read 2 more answers
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Answer:

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7 0
3 years ago
A bit hard for me !!!!!
Annette [7]
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Answer:

0t=8

Step-by-step explanation:

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3 years ago
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