3 years ago

A Question 2 (2 points) Retake question

Mathematics

1 answer:

Nataly [62]3 years ago

5 0

Answer:

5 to 2

Step-by-step explanation:

you divide both numbers by 2

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Answer:

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Step-by-step explanation:

Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

$\binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{60}{3}=\frac{60!}{3!(60-3)!}\\\\\binom{60}{3}=\frac{60!}{3!(57)!}\\\\\binom{60}{3}=\frac{60*59*58}{3*2*1}\\ \\\binom{60}{3}=34220$

Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.

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