Answer: The area is approximately 314 ft^2
Step-by-step explanation:
Well if the diameter is 20 feet then the radius will be 10 because the radius is half the diameter, and to find the area of a circle, you use the formula
A= 
where A is the area and pi times the radius squared.
We will represent pi by 3.14
A= 3.14* 10^2
A= 3.14 * 100
A = 314
<span>1) Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). y = 1/2x
2)Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1).
m = (-9 - 1) / (6 - 7) = -10/-1 = 10
y + 9 = 10 (x - 6)
y = 10x - 69
3) A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write the equation of the given line in the traditional version of the point-slope form of a line.
4)Write the point-slope form of the equation of the line that passes through the points (-3, 5) and (-1, 4).
m = (5 - 4) / (-3 - -1) = 1/-2
y - 5 = (-1/2) (x +3)
y = (-1/2)x + 7/2
5) Write the point-slope form of the equation of the line that passes through the points (6, 6) and (-6, 1).
m = (6-1)/(6 - -6) = 5 / 12
y - 6 = (5/12) (x-6)
y = (5/12)x + 17 / 2
6) Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).
m = (2 - -4) / (-8 -1) = 6 / -7
y - 2 = (-6/7) (x + 8)
y = (-6/7)x - 50 / 7
7) Write the point-slope form of the equation of the line that passes through the points (5, -9) and (-6, 1).
m = (-9 - 1) / (5 - -6) = -10 / 11
y + 9 = (-10 / 11) (x - 5)
y = (-10 / 11)x -49/11
</span>
Answer:
- A. (x + 16) + (6x − 4) = 180
Step-by-step explanation:
Inscribed quadrilateral has opposite angles supplementary.
<u>So</u>
or
<u>Since</u>
- m∠A = x + 16,
- m∠B = x,
- m∠C = 6x - 4,
- m∠D = 2x + 16
we can use either pair of angle measures to work out the value of x and then find the value of each angle.
<u>We can verify the first option is the only correct one.</u>
- m∠A + m∠C = 180°
- (x + 16) + (6x − 4) = 180
Use these equations when converting polar equations to parametric equations:
We know that 
, so substitute that into both equations for x and y.
Now, replace 
with any variable that you want to represent the parametric equations in. I'll use the standard variable, 
Thus, represented in parametric form is:
Let me know if you need any clarifications, thanks!
~ Padoru
