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2 years ago

The first number in a pattern is 246, and the rule is subtract 10. What is the next number in the pattern?

Mathematics

2 answers:

kumpel [21]2 years ago

3 0

Answer : 236
246 - 10 = 236

amm18122 years ago

3 0

Answer:

236

Step-by-step explanation:

246 minus 10=236 thats it

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Find the 25th of sequence 3,5,7,9,11

zubka84 [21]

Answer: The 25th term of the sequence is 75

Step-by-step explanation:

The given sequence depicts an arithmetic progression. The consecutive terms differ by a common difference. We will apply the formula for arithmetic progression.

Tn = a + (n-1)d

Tn = The value of the nth term of the arithmetic sequence.

a = first term of the sequence.

d = common difference (difference between a term and the consecutive term behind it)

n = number of terms in the sequence.

From the information given,

a = 3

d = 5-3 = 7-5 = 2

We want to look for the 25th term, T25

So n = 25

T25 = 3 + (25-1)2 = 3+ 24×2

T25 = 3 + 72 = 75

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3 years ago

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tatyana61 [14]

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Step-by-step explanation:

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3 years ago

Given that tan^2 theta=3/8,what is the value of sec theta?

algol [13]

Answer:

The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = $\frac{3}{8}$

Or, tanФ = $\sqrt{\frac{3}{8} }$

∵ tanФ = $\frac{Perpendicular}{Base}$

So, $\frac{Perpendicular}{Base}$ = $\sqrt{\frac{3}{8} }$

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( $\sqrt{3}$ )² + ( $\sqrt{8}$ )²

Or, Hypotenuse² = 3 + 8 = 11

Or, Hypotenuse = ( $\sqrt{11}$ )

Now SecФ = $\frac{Hypotenuse}{Base}$

or, SecФ = $\frac{\sqrt{11}}{\sqrt{8}}$ = $\sqrt{\frac{11}{8} }$

Second Method

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 + tan²Ф

or, Sec²Ф = 1 + $\frac{3}{8}$

Or, Sec²Ф = $\frac{11}{8}$

Or, SecФ = $\pm \sqrt{\frac{11}{8}}$

Hence The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ . Answer

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Answer:

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Step-by-step explanation:

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