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Ahat [919]
3 years ago
15

You want to connect the LAN port on a router to the uplink port on a switch. The switch does not support auto-MDI. Which type of

cable should you use?A. CrossoverB. LoopbackC. RolloverD. Straight-through
Computers and Technology
1 answer:
kirza4 [7]3 years ago
3 0

Answer: Crossover

Explanation:

Based on the information given in the question, the type of cable that should be used is the crossover cable.

Crossover cable is used for a direct connection of computing devices. A crossover cable is typically used for the connection of computing devices that are of identical types.

Since the LAN port on a router is to be connected to the uplink port on a switch and the switch does not support auto-MDI, the crossover cable can be used.

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A set of rules that specify how each code statement must be written is called the ____ of the programming language.
Helga [31]

Answer:

syntax

Explanation:

7 0
2 years ago
There are several methods of updating information and data on a webserver. We must consider who performs those updates upfront w
Thepotemich [5.8K]

Answer:

RTMC pro, HTML server-sent and Java Software Development Kit

Explanation:

<u>RTMC pro</u>:  The setup of RTMC pro is done automatically and there is provision of several elements to upload and store data on the server using screens. Screens are usually saved as files and then integrated to an internal or external server.

<u>HTML server-sent</u> : This is a way for webpages to communicate with the webserver. In this method, for ever HTML page there is an associated script present on the server side that will continuously provide realtime data update. This scrip will have to be configured with the data you want to update.

<u>Java Software Development Kit</u> : JAVA SDK is used to build software/applications on Java. This permits programmers to develop applications or applets to perform data updating on the servers. The developped applets can be used with internal servers as well as third party servers.

5 0
3 years ago
Read 2 more answers
Python
andreyandreev [35.5K]

Answer:

<h2>1)   </h2>

h = 19  # h is already assigned a positive integer value 19

i = 1  # used to calculate perfect square

q = 0   # stores the sum of the perfect squares

while q < h:  

# this loop executes until value of number of perfect squares is less than h

   q = q + (i*i)  # to calculate the sum of perfect squares

   i = i + 1  # increments i by 1 at every iteration

print(q) # displays the sum of perfect squares

Output:

30

Explanation:

Here we see that the sum of the perfect square is printed in the output i.e. 30. If we want to assign value 4 to q then we should alter the code as  following:  

h = 19

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   q = q + 1

   i = i + 1  

print(q)  

If you want to take input from the user and also display the perfect squares in output you can use the following code:

h = int(input('Enter the value of h: ')) #takes value of h from user

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   print(i*i) #displays the perfect squares of h

   q = q + 1

   i = i + 1    

print(sum_of_ps)   #displays sum of perfect squares

print(q) #displays number of perfect squares whose value is less than h

Output:

1

4

9

16

30

4

<h2>2)</h2>

# k and m are already assigned positive integers 10 and 40

k = 10  

m = 40  

i = 1  # i is initialized to 1

q = 0  # q stores the number of perfect squares between k and m

while i*i < m:  # loop computes perfect square of numbers between k and m

   if i*i > k:          

       q = q + 1  # counts the number of perfect squares

   i = i + 1  #increments the value of i at each iteration

print (q) # prints the no of perfect squares between k and m

If you want to display the perfect squares too use , add print(i*i) statement after if statement  if i*i > k:        

Output:

3

<h2>3)</h2>

def Fibonacci(n):  # method Fibonacci which has an integer parameter n

   if n <= 1:  # if the value of n is less than or equals to 1

       result = n  # stores the value of n into result

   elif n > 1:  # else if the value of n is greater than 1

       result = Fibonacci(n-1) + Fibonacci(n-2)  

# calls Fibonacci method recursively to associate nth value of Fibonacci #sequence with variable result

   return result     #returns the final value stored in result variable

print(Fibonacci(8))

#calls Fibonacci function and passes value 8 to it

Output:

21

8 0
3 years ago
The sender side of rdt3.0 simply ignores (that is, takes no action on) all received packets that are either in error or have the
Rom4ik [11]

Answer:

It might not work efficiently.

Explanation:

The function of the protocol rtd3.0 is to transfer data to a receiver from a sender.

As soon as the receiver received the packet transferred by the sender, we respond acknowledge (Ack) to the sender so that sender can confirm the receiver has gotten it.  

The receiver will not send any acknowledgment if the packet he receives are such that bits contain error or not in order.

After that timeout, the packet will be re-transmitted by the sender.

It is then possible the protocol might seem to be inefficient if a packet is sent many times, because other packets will have to wait to sent until the current packet is sent successfully.

The solution to prevent this kind of issue is to allow for the occurrence of premature timeouts.

7 0
3 years ago
Which file format results in the smallest file size
Agata [3.3K]
Kilobytes. That the smallest type of file you have on a computer.
6 0
4 years ago
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