TLDR: 241 clients will be taking +3 vacations.
This is a common example of representative scale size, or sample size. In selecting a small amount of people at random from a larger group, one can estimate the amount of people in the large group picking a specific answer based on a smaller, but proportionate, group size.
In the sample size, 21 of the 45 tested people said that they would go on more than three vacations a year, and this scale is supposedly proportional to the total group. Therefore, we can use a simple proportion to estimate the amount of people who would also say that they are going on more than three trips a year:
21 would ‘N’ would
————— = ——————
45 total 516 total
where N represents the number of people in the big group that would go on more than three trips a year.
Solve the proportion by cross-multiplication:
45N = 10,836
N = 240.8 people, or 241 people.
Based on the sample data, 241 people out of the 516 total will be taking more than three vacations a year.
Answer:
Step-by-step explanation:
1). Since, XM is the radius of the circle,
Therefore, area of the circle = 
= 
= 
= 452.39 units²
2). Circumference of a circle = 2πr
= 2π(XM)
= 2π(12)
= 24π
= 75.40 units
3). By applying Pythagoras theorem in ΔYXM,
YM² = XY² + XM²
(43)²= (XY)² + (12)²
1849 - 144 = (XY)²
XY = 41.29 units
4). tan(∠M) =
= 
m∠M = 
= 73.79°
5). Area of ΔXYM = 
= 
= 247.74 square units
6). Area of the minor sector created by ΔXYM = 
= 
= 92.73 units²
Answer:

Step-by-step explanation:
Express the 2 fractions with a common denominator of 21
multiply numerator/denominator of first fraction by 3
multiply numerator/denominator of second fraction by 7
- 
=
- 
= 
Answer:
The area of the clock 
Step-by-step explanation:
We have been given the face of the clock that is 
So that is also the circumference of the clock.
Since the clock is circular in shape.
So 
From here we will calculate the value of radius
of the clock that is circular in shape.
Then 
Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.
Now 
So the area of the face of the clock =