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dmitriy555 [2]
3 years ago
15

NEED HELP! GIVING BRAINLIEST!

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0
A, in one day there are 6 clients and for each day multiplied it equals C for example if you were to plug in 1 for d
6(1)=6 and so on which shows the total clients.
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Is the triangle obtuse, acute, equilateral or right?
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Answer:

  obtuse

Step-by-step explanation:

The law of cosines tells you ...

  b² = a² +c² -2ac·cos(B)

Substituting for a²+c² using the given equation, we have ...

  b² = b²·cos(B)² -2ac·cos(B)

We can subtract b² to get a quadratic in standard form for cos(B).

  b²·cos(B)² -2ac·cos(B) -b² = 0

Solving this using the quadratic formula gives ...

  \cos(B)=\dfrac{-(-2ac)\pm\sqrt{(-2ac)^2-4(b^2)(-b^2)}}{2b^2}\\\\\cos(B)=\dfrac{ac}{b^2}\pm\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

  \cos(B)=\dfrac{ac}{b^2}-\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.

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Step-by-step explanation:

<em><u>Plz mark as brainliest if correct! Have a nice day!!!</u></em>

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