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Gekata [30.6K]
3 years ago
11

I need to find the vertex for 3x^2 + 2x - 1

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0

Answer:

4 easy

Step-by-step explanation:

hope it helps

Nataliya [291]3 years ago
6 0
4 hope it’ll help. Hubjknhj
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Find the linearization L(x) of the function at a. f(x) = x^4 + 2x^2, a = 1
gregori [183]

The equation of the tangent line at x=1 can be written in point-slope form as

... L(x) = f'(1)(x -1) +f(1)

The derivative is ...

... f'(x) = 4x^3 +4x

so the slope of the tangent line is f'(1) = 4+4 = 8.

The value of the function at x=1 is

... f(1) = 1^4 +2·1^2 = 3

So, your linearization is ...

... L(x) = 8(x -1) +3

or

... L(x) = 8x -5

8 0
3 years ago
How to evaluate an algebraic expression?
irinina [24]

"Evaluation" mostly means "simplifying an expression down to a single numerical value". Sometimes you will be given a numerical expression, wher all you have to do is simplify; that is more of an order-of-operations kind of question.

Hope this helped                                     BTW can I have brainliest that would help me

8 0
3 years ago
Factor the expression completely.8y - 36
Naily [24]

Answer:

A. 4(2y-9)

Step-by-step explanation:

Both terms are divisable by 4 and would bring them to the smallest whole degree

8 0
3 years ago
Read 2 more answers
In a class with 42 students, 22 like blue and 27 like red. If 6 no like either colours. Find :- a) How many students like both r
andrezito [222]

27+22=49

so your question doesnt really make sense, can u re-word it and make sure your problem is correct

7 0
4 years ago
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Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

#SPJ1

8 0
2 years ago
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