Answer:
35
Step-by-step explanation:
Answer:
Dennis need 288.91 square inches of construction paper for his project.
Step-by-step explanation:
Dennis is cutting construction paper into rectangles for a project.
He needs to cut one rectangle that is 12 inches times 15 1/4 inches
First convert the mixed fraction to improper fraction
![15\frac{1}{4} = \frac{(15\times4) + 1}{4} = \frac{61}{4}](https://tex.z-dn.net/?f=15%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B%2815%5Ctimes4%29%20%2B%201%7D%7B4%7D%20%3D%20%5Cfrac%7B61%7D%7B4%7D)
So the area of 1st rectangle is
![A_1 = 12\times \frac{61}{4} = 183 \: in^{2}](https://tex.z-dn.net/?f=A_1%20%3D%2012%5Ctimes%20%5Cfrac%7B61%7D%7B4%7D%20%3D%20183%20%5C%3A%20in%5E%7B2%7D)
He needs to cut another rectangle that is 10 1/3"" x 10 1/4""
The symbol " means inches
First convert the mixed fraction to improper fraction
![10\frac{1}{3} = \frac{(10\times3) + 1}{3} = \frac{31}{3}](https://tex.z-dn.net/?f=10%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B%2810%5Ctimes3%29%20%2B%201%7D%7B3%7D%20%3D%20%5Cfrac%7B31%7D%7B3%7D)
![10\frac{1}{4} = \frac{(10\times4) + 1}{4} = \frac{41}{4}](https://tex.z-dn.net/?f=10%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B%2810%5Ctimes4%29%20%2B%201%7D%7B4%7D%20%3D%20%5Cfrac%7B41%7D%7B4%7D)
So the area of 2nd rectangle is
![A_2 = \frac{31}{3}\times \frac{41}{4} = 105.91 \: in^{2}](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7B31%7D%7B3%7D%5Ctimes%20%5Cfrac%7B41%7D%7B4%7D%20%3D%20105.91%20%5C%3A%20in%5E%7B2%7D)
The total construction paper needed for this project is
![A = A_1 + A_2\\\\A = 183 + 105.91\\\\A = 288.91 \: in^{2}](https://tex.z-dn.net/?f=A%20%3D%20A_1%20%2B%20A_2%5C%5C%5C%5CA%20%3D%20183%20%2B%20105.91%5C%5C%5C%5CA%20%3D%20288.91%20%5C%3A%20in%5E%7B2%7D)
Therefore, Dennis need 288.91 square inches of construction paper for his project.
Answer:
P=12.8 in A=33
Step-by-step explanation:
Well those triangles are congruent and we can solve it by proportion, so we have :
We can solve them by proportions because they are congruent. So, we can do it .
X-perimeter of triangle with side 3.2.
Here we make proportions :
3.2:x=5.8:23.2
3.2*23.2=5.8*x
x=12.8
Now, let find area
3.2:Y=5.8:59.8
3.2*59.8=5.8*x
Y=32.99=33
![{\bf \red {\huge{answer : }}}](https://tex.z-dn.net/?f=%20%7B%5Cbf%20%5Cred%20%7B%5Chuge%7Banswer%20%3A%20%7D%7D%7D)
The money increased from 600 pounds to 621 pounds.
621 - 600 = 21
so , the money increased more 21 pounds.
![\pink {\sf{hence , \frac{21}{621} \times 100 }}](https://tex.z-dn.net/?f=%20%5Cpink%20%7B%5Csf%7Bhence%20%2C%20%5Cfrac%7B21%7D%7B621%7D%20%5Ctimes%20100%20%7D%7D)
![\red{= \frac{21}{\cancel{621}} \times \cancel{100 } }](https://tex.z-dn.net/?f=%20%5Cred%7B%3D%20%20%5Cfrac%7B21%7D%7B%5Ccancel%7B621%7D%7D%20%5Ctimes%20%20%5Ccancel%7B100%20%7D%20%20%7D)
![\red{= \frac{21}{\cancel{6.21}} \times \cancel{1 } }](https://tex.z-dn.net/?f=%20%5Cred%7B%3D%20%20%5Cfrac%7B21%7D%7B%5Ccancel%7B6.21%7D%7D%20%5Ctimes%20%20%5Ccancel%7B1%20%7D%20%20%7D)
![\red{= \frac{\cancel{21}}{\cancel{6.21}} }](https://tex.z-dn.net/?f=%20%5Cred%7B%3D%20%20%5Cfrac%7B%5Ccancel%7B21%7D%7D%7B%5Ccancel%7B6.21%7D%7D%20%7D)
![\red{= \frac{3 \frac{79}{207} }{1} }](https://tex.z-dn.net/?f=%20%5Cred%7B%3D%20%20%5Cfrac%7B3%20%5Cfrac%7B79%7D%7B207%7D%20%7D%7B1%7D%20%7D)
![\red{= 3 \frac{79}{207} }](https://tex.z-dn.net/?f=%20%5Cred%7B%3D%20%203%20%5Cfrac%7B79%7D%7B207%7D%20%7D)
Therefore , the dog's weight increased by 3 79/207%
Answer:
D is 36080
Step-by-step explanation:
D is the largest since A is 3.608, B is 360.8, C is 36.08
When dividing, the smaller decimal points will be larger, but if you multiple, the numbers shrink.