What is x ÷ t/4 = -6/13

Step-by-step explanation:

You just have to plug the numbers they give you into the equation. For the first one, you have 0 + 5y = 10; 5y = 10; y = 2. For the second one, x + 5(0) = 10; x + 0 = 10; x = 10. And lastly, for the third one, x + 5(6) = 10; x + 30 = 10; x = -20.

7 0

3 years ago

1. Explain why n root a^n= |a| when n is even, but not when n is odd.

kogti [31]

Step-by-step explanation:

In the expression a^n, for integer values of n greater than 1, there are n factors. For example, a^2 = a * 2 (2 factors), a^3 = a * a * a (3 factors), etc.

For a non-negative value of a, a^n is non-negative for all values of n.

If a is negative, and n is even, then a^n is non-negative.

If a is negative, and n is odd, then a^n is negative.

|a| is non-negative for all values of a.

sqrt_n(a^n) is negative for negative a and odd n, but |a| is always non-negative, so sqrtn(a^n) cannot equal |a| for odd n.

8 0

3 years ago

Find the lateral and total surface area for the cone. If necessary, round to the nearest tenth and leave the

bija089 [108]

9514 1404 393

Answer:

262.2π cm²
392.16π cm²

Step-by-step explanation:

The lateral surface area is the product of half the circumference, and the slant height:

LA = πrh = π(11.4 cm)(23 cm) = 262.2π cm²

The total surface area adds the area of the base to that:

A = πr² +LA = π(11.4 cm)² +262.2π cm² = (129.96 +262.2)π cm²

A = 392.16π cm²

3 0

2 years ago

Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic

Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

b) $s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

8 0

3 years ago

I JUST WANNA PASS MY SOPHOMORE YEAR BUT I SUCK AT MATH!!!!! PLEASE HELP!!!!!!

Natasha2012 [34]

Mr. Sanchez's class: 1.65p

Mr. Kelly's class: 1.36j

where p = fruit pies and j = fruit juice

____________________________________________________________

(a) Creating a system of equations

p + j = 79

1.65p + 1.36j = 118.17

are your system of equations

____________________________________________________________

(a) Solving the system of equations for p and j

Solve for p in the first equation. Subtract j from both sides.

p = 79 - j

____________________________________________________________

Plug p into the second equation.

1.65(79 - j) + 1.36j = 118.17

Distribute 1.65 inside the parentheses.

130.35 - 1.65j + 1.36j = 118.17

Combine like terms.

130.35 - 0.29j = 118.17

Subtract 130.35 from both sides.

-0.29j = -12.18

Divide both sides by -0.29.

j = 42

____________________________________________________________

Plug j into the first equation.

p + (42) = 79

Subtract 42 from both sides.

p = 37

____________________________________________________________

(b) To find out how much each class earned

Now plug in p and j into Mr. Sanchez's class and Mr. Kelly's class equations (at the top).

Mr. Sanchez's class: 1.65(37) = 61.05

Mr. Kelly's class: 1.36(42) = 57.12

____________________________________________________________

(c) To see how much more Mr. S's class earned

Subtract 57.12 from 61.05.

61.05 - 57.12 = 3.93

____________________________________________________________

(a)

p + j = 79

1.65p + 1.36j = 118.17

(b)

Mr. Sanchez's class earned more money (61.05 > 57.12).

(c)

Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class.

3 0

3 years ago

What is x ÷ t/4 = -6/13​

What is x ÷ t/4 = -6/13