bear in mind that one can always get the common ratio by simply dividing any of the terms by the one before it namely, say 18÷12 or 27÷18.
![\bf 12~~,~~\stackrel{12\cdot \frac{3}{2}}{18}~~,~~\stackrel{18\cdot \frac{3}{2}}{27}\qquad \qquad \stackrel{\textit{common ratio}}{r = \cfrac{3}{2}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%2012~~%2C~~%5Cstackrel%7B12%5Ccdot%20%5Cfrac%7B3%7D%7B2%7D%7D%7B18%7D~~%2C~~%5Cstackrel%7B18%5Ccdot%20%5Cfrac%7B3%7D%7B2%7D%7D%7B27%7D%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Bcommon%20ratio%7D%7D%7Br%20%3D%20%5Ccfrac%7B3%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf S_8=12\left( \cfrac{1-\left( \frac{3}{2} \right)^8}{1-\frac{3}{2}} \right)\implies S_8=12\cdot \cfrac{\frac{-6305}{256}}{-\frac{1}{2}}\implies S_8=12\cdot \cfrac{6305}{128} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill S_8=\cfrac{18915}{32}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20S_8%3D12%5Cleft%28%20%5Ccfrac%7B1-%5Cleft%28%20%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%5E8%7D%7B1-%5Cfrac%7B3%7D%7B2%7D%7D%20%5Cright%29%5Cimplies%20S_8%3D12%5Ccdot%20%5Ccfrac%7B%5Cfrac%7B-6305%7D%7B256%7D%7D%7B-%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20S_8%3D12%5Ccdot%20%5Ccfrac%7B6305%7D%7B128%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20S_8%3D%5Ccfrac%7B18915%7D%7B32%7D~%5Chfill)
The inequality Is showing that -1 is less than or equal to t. If t was -2 then this would not make sense, since -1 is greater than -2.
Hope this helped
2306421 and 2302972 are 3349, through the difference you can draw a number line and put 2306421 and 2302972 on two other sids. Then, shade the difference between the two numbers on the number line and label the distance 3349.
Answer:
120 buckets
Step-by-step explanation:
If there are 15 teams and each team gets the same number of buckets (8 buckets as mentioned in the problem), then you can multiply 15 by 8 to get 120.
15 teams * 8 buckets = 120 total buckets
B is the correct answer.....
