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scoundrel [369]
2 years ago
14

Every year, Alice's family runs the sand castle contest during the Fun in the Sun beach festival. Alice's job is to deliver empt

y buckets to the teams. This year, Alice hands out the same number of buckets to each of the 15 teams in the contest. Each team gets 8 buckets.
Use an equation to find the total number of buckets Alice delivers.
Mathematics
1 answer:
seropon [69]2 years ago
8 0

Answer:

120 buckets

Step-by-step explanation:

If there are 15 teams and each team gets the same number of buckets (8 buckets as mentioned in the problem), then you can multiply 15 by 8 to get 120.

15 teams * 8 buckets = 120 total buckets

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Which is the correct input-output table for the function f(x) = 3x2 - 1+4?
krok68 [10]

Answer:

the question is incorrect. please write your points as coordinates or scan the diagram.

4 0
2 years ago
Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.
MrMuchimi
A random variable following a binomial distribution over n trials with success probability p has PMF

f_X(x)=\dbinom nxp^x(1-p)^{n-x}

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1

The mean is given by the expected value of the distribution,

\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}

The remaining sum has a summand which is the PMF of yet another binomial distribution with n-1 trials and the same success probability, so the sum is 1 and you're left with

\mathbb E(x)=np=126\times0.27=34.02

You can similarly derive the variance by computing \mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2, but I'll leave that as an exercise for you. You would find that \mathbb V(X)=np(1-p), so the variance here would be

\mathbb V(X)=125\times0.27\times0.73=24.8346

The standard deviation is just the square root of the variance, which is

\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834
7 0
3 years ago
Students were surveyed about their favorite colors. 1/4 of the students preffered red, 1/8 of the students preffed blue, and 3/5
lapo4ka [179]
27 is how much kids did the survey because I added all the fractions together like how the question did 3/5 which is 3 × 5 = 15
8 0
3 years ago
0.8 is 10 times as great as what decimal
kondor19780726 [428]
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Similarly, to know the decimal that is less that 0.8 by 10 times, simply divide 0.8 by 10 as follows:
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This means that 0.8 is 10 times larger than 0.08
5 0
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Sergeeva-Olga [200]

Answer:

C

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 10, 10 ], thus

f(b) = f(10) = 10² + 9(10) + 18 = 100 + 90 + 18 = 208

f(a) = f(- 10) = (- 10)² + 9(- 10) + 18 = 100 - 90 + 18 = 28, thus

average rate of change = \frac{208-28}{10-(-10)} = \frac{180}{20} = 9

3 0
3 years ago
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