<span>1) 3x-2=x+10
</span><span>Now, lets solve this step-by-step.
</span><span>
3x - 2 = x + 10
-x -x
</span><span>
</span><span>3x - x = 2x 2x - 2 = 10
</span><span>
</span><span>2x - 2 = 10
</span>2x - 2+2 = 10+2 The inverse operation helps isolate the variable.
<span>
2x = 12
2x/2 = 12/2
x = 12/2
x = 6</span><span>
Answer: x = 6
2) x + 4 = 19 - 2x </span>
We can solve this much faster
x + 4 = 19 - 2x
+2x
x+2x = 3x
3x + 4 = 19
-4 -4
19-4 = 15
3x= 15
3x/3 = 15/3
x= 5
Answer: x = 5
3) <span>8x - 20 = x + 15
Much faster now!!
8x - 20 = x + 15
-x
8x-x = 7x
7x - 20 = 15
+20 +20
15+20 = 35
7x = 35
7x/7 = 35/7
x = 35/7
x = 5
Answer: x= 5</span>
Answer:
d. {(1,2),(2,2),(3,2),(4,2),(5,2),(6,2)}
Step-by-step explanation:
First one can be any of the six outcomes
A) 8/16 = 1/2; YES
B) 2^-1 = 1/2^1 = 1/2; YES
C) 2^0 = 1; NO
D) 2^1 = 2; NO
Hope this helped!
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
<span>
<span>
</span>
2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
</span><span>
<span>
</span>
3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
</span><span>
<span>
</span>
4. complete the squre and expand
</span>
so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
