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FromTheMoon [43]
3 years ago
7

105,159 rounded to the nearest ten thousand

Mathematics
2 answers:
ahrayia [7]3 years ago
8 0


ok when rounding ,, 105 ,159 to the nearest ten-thousandth ...

                                  ^^ ok 1 is the ten thousandth so is 0 bigger or smaller than 4?

no so your answer would be 100.000 or also written as 100

ivolga24 [154]3 years ago
6 0

For this case we have the following number:

105,159

By definition we have:

thousand place: five-digit number greater than zero.

On the other hand we have as a rule:

When the previous number is greater than or equal to five, then the next number increases by one.

So we have to round off to the nearest ten thousand:

105,159 = 110,000

Answer:

105,159 rounded to the nearest ten thousand is:

105,159 = 110,000

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Step-by-step explanation:

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step-by-step explanation:

i can't see the rest of the question so i don't know the answer choices but:

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prohojiy [21]
Okay so lets look at the equation given
a ^{2} + {b}^{2} = {c}^{2}
this is the Pythagorean theorem, this equation holds true to all right angle triangles.

for the "a" and "b" terms must be the two shortest lengths and "c" must be the longest length.
why? because "c" represents the hypotenuse in this theorem and the hypotenuse is by definition the longest side of a right triangle.

(side note: always draw a picture, it helps a lot if you doodle a bit to get an idea of what you are working with)

we are given three lengths : 3 , 4, and 5 (im ignoring the measurements for now)

we can look at it two ways with a picture and through algebra

try to draw a right triangle with the given info. you'll see there are only two cases were this is possible the picture above is one case where this is not possible

now we can look at this algebraically
a = 3 \\ b = 4 \\ c = 5
(but "a" and "b" can swap lengths)

now with the Pythagorean theorem we can see how this plays out
{a}^{2} + {b}^{2} = {c}^{2} \\ {3 }^{2} + {4}^{2} = {5 }^{2} \\ 9 + 16 = 25 \\ 25 = 25
and heres with "a" and "b" lengths swapped
{4}^{2} + {3}^{2} = {5}^{2} \\ 16 + 9 = 25 \\ 25 = 25
now here's a case when we let 5 , our longest length , become a leg and let one our shorter lengths take the place of "c"

a = 5 \\ b = 3 \\ c = 4 \\ {5}^{2} + {3}^{2} = {4}^{2} \\ 25 + 9 = 16 \\ 34 = 16 \:
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hope this helped you out

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3 years ago
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Answer:

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Step-by-step explanation:

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Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
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The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.

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For the median you want o line all of your number up from least to greatest and then find the middle number.

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Your median is 52

The mode is the number that is listed most often

49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times

So, your mode is 49




4 0
3 years ago
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