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2 years ago

I’m working on 3 and 4 only maybe if I can have some explanation so I can understand and do more of these next week.

Mathematics

1 answer:

guapka [62]2 years ago

7 0

4.b.

Answer: See below.

Step-by-step explanation:

<h2>For the equation f(x) = 2x</h2>

3.a. f(6) means use x = 6 in the equation f(x) = 2x

so f(6) would be f(6)= 2(6)

f(6) = 12

3.b. f(-11) = 2(-11)

f(-11) = -22

3.c. f(2.75) = 2(2.75)

f(2.75) = 5.5

3.d. This is turned around. We are told f(x)=20, so what would x need to be for f(x) to be 20? Since f(x) = 2x, we can say 20 = 2x. Therefore x = 10

f(10) = 20

The rest of (3) are solved in the same fasion.h

<h2>For the equation f(x)= 5x+50</h2>

4.a. f(7) = 5(7)+50

f(7) = 85

4.b. f(-12)

f(-12) = 5*(-12)+50

f(-12) = -60

Continue in the same fashion for these types of problems.

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Answer:

Step-by-step explanation:

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2 years ago

Calculate limits x>-infinity -2x^5-3x+1

Lera25 [3.4K]

Given:

The limit problem is:

$\lim_{x\to -\infty}(-2x^5-3x+1)$

To find:

The value of the given limit problem.

Solution:

We have,

$\lim_{x\to -\infty}(-2x^5-3x+1)$

In the function $-2x^5-3x+1$ , the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

$\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$

Therefore, $\lim_{x\to -\infty}(-2x^5-3x+1)=\infty$ .

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2 years ago

Domain and range of y=-.50x+12

Alja [10]

Domain: all real numbers
Range: y<0

3 0

3 years ago

What is the solution to this system of equations?

dalvyx [7]

There is no solution.

Step-by-step explanation:

Given:

y = 2x + 1

4x - 2y = 4

Substitute y = 2x + 1 into 4x - 2y = 4

4x - 2(2x + 1) = 4

4x - 4x - 2 = 4

0x = 4 + 2

0x = 6

Anything to the multiple of zero is zero. Hence 0x = 0, and 0 ≠ 6

So there is no solution to the equation.

8 0

2 years ago

Can someone help and give me a step by step explanation please?!

vitfil [10]

9514 1404 393

Answer:

∠QSR = 78°
∠SQR = 51°

Step-by-step explanation:

The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...

∠QSR = 2×∠QTR

∠QSR = 2×39°

∠QSR = 78°

Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...

∠QSR + 2(∠SQR) = 180°

78° + 2(∠SQR) = 180° . . . . fill in the value we know

2(∠SQR) = 102° . . . . . . . . . subtract 78°

∠SQR = 51° . . . . . . . . . . . . .divide by 2

7 0

2 years ago