The area of the trapezoid can be calculated through the equation,
A = (b₁ + b₂)h / 2
where b₁ and b₂ are the bases and h is the height. Substituting the known values from the given,
A = (25mm + 32mm)(15 mm) / 2
A = 427.5 mm²
Since there are two trapezoids in the necklace, the area calculated is to be multiplied by two to get the total area.
total area = (427.5 mm²)(2)
<em>total area = 855 mm²</em>
Answer:
b=i*
or -i*
Step-by-step explanation:
11b^2-9=-68
11b^2=-59
b^2=-59/11
b=i* or -i*
"i" in this case is an imaginary number, equal to 
if you haven't learned about these yet, something is wrong with the question
Since he descended 12 meters, we subtract this from the overall height of Mount Ka'ala, so then we are only calculating how high ABOVE the sea level it is.
1232 - 12 = 1220
The height of Mount Ka'ala is therefore 1,220 meters.
To calculate how much a fifth of Mount Ka'ala is (since the ranger station is 2/5's up), we would divide this number by 5
1220 ÷ 5 = 244
Since ONE fifth of the height is 244 meters, TWO fifths would be double that amount.
244 x 2 = 488
488 meters.
The ranger station is 488m above sea level.
f(b) = -1/6b + 8. Is the function rule if you want. further explanation just ask.
Answer:
The equation of the line would be y = 4/9x
Step-by-step explanation:
In order to find the equation, we first need to find the slope. We can do this by using the slope equation with the points.
m(slope) = (y2 - y1)/(x2 - x1)
m = (9 - 0)/(4 - 0)
m = 9/4
Now that we have this, we can use point-slope form along with one of the points to get the equation.
y - y1 = m(x -x1)
y - 0 = 4/9(x - 0)
y = 4/9x
