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kupik [55]
3 years ago
8

What are two decimals with thousandths that would give 0.2 when rounded to the nearest tenth and 0.20 when rounded to the neares

t hundredth?
Plzz help me I don't get the question!!!
Mathematics
1 answer:
ale4655 [162]3 years ago
3 0
To answer your questions, 3.216 and 7.203.
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An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
Can someone plz help me with this one problem plzzz!!!
tresset_1 [31]

so, you just use the x's from the table and plug them into the equation to find the y.

y=(1)+9

y=10

y=(2)+9

y=11

y=(3)+9

y=12

y=(4)+9

y=13

i hope this helps :)

6 0
3 years ago
A trapezoid is shown. The lengths of the bases are 4 and 8. The height of the altitude is 4. What is the area of the trapezoid?
katrin [286]
It would be 24 units^2 because the middle is 16 and the two triangles are 4 each
3 0
3 years ago
Read 2 more answers
Give a counterexample for the statement: 'All square roots are irrational numbers'. Explain your reasoning.
galben [10]
A counterexample for the statement 'All square roots are irrational numbers.' is the square root of 9.  This is because when simplified, the answer is 3.  

For a number to be irrational, it can't be expressed in fractional form.  However, 3 can be expressed in fractional form as 3/1.
5 0
3 years ago
What is 2 times 4 plus 20 and times 3?
Gennadij [26K]

Answer:

84

Step-by-step explanation:

5 0
3 years ago
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