Answer:
Step-by-step explanation:
We can get this done by using the code
def digits(n):
count = 0
if n == 0:
return 1
while (n > 0):
count += 1
n= n//10
return count
Also, another way of putting it is by saying
def digits(n):
return len(str(n))
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print(digits(25)) # Should print 2
print(digits(144)) # Should print 3
print(digits(1000)) # Should print 4
print(digits(0)) # Should print 1
Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.
Thanks
Answer:20
Step-by-step explanation:
8 members=8mins
1 member=80 mins
20members=2.5mins
13a) y = 0.45x
13b) 52 * 0.45 = 23.4
13c) I will let u figure this one out
$12.35 because if u cross multiply 120/100 and 14.82/x u can solve algebraically and get 12.35
