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rodikova [14]
3 years ago
9

A widget company produces 25 widgets a day, 5 of which are defective. Find the probability of selecting 5 widgets from the 25 pr

oduced where none are defective.
Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

0.292

Step-by-step explanation:

When we select the first widget, there are 20 good widgets from 25 total.

When we select the second widget, there are 19 good widgets from 24 total.

So on and so forth.

So the probability is:

P = (20/25) (19/24) (18/23) (17/22) (16/21)

P = 0.292

Alternatively, we can calculate this using combinations.

We are selecting 5 widgets from a total of 25. ₂₅C₅

From the 5 defective widgets, we want to select 0. ₅C₀

From the 20 non-defective widgets, we want to select 5. ₂₀C₅

So the probability is:

P = (₅C₀ ₂₀C₅) / ₂₅C₅

P = 0.292

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Answer:

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Step-by-step explanation:

The first step to solve this problem is finding the daily kcal intake of the dogs.

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x = 324*3.5

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His daily intake is of 1134 kcals.

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There are 3.6g of fat in 100 kcals of energy. How many g of fat are there in 1134 kcals?

3.6g - 100 kcals

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100x = 1134*3.6

x = \frac{1134*3.6}{100}

x = 11.34*3.6

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The food contains 25.6 IU of Vitamin D3 in 100 kcals of energy. what is his daily Vitamin D inake?

Similar logic as above.

25.6IU - 100 kcals

x IU - 1134 kcal

100x = 1134*25.6

x = \frac{1134*25.6}{100}

x = 11.34*25.6

x = 290.304IU

His daily Vitamin D intake is 290.304 IU.

7 0
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