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astra-53 [7]
2 years ago
11

Of the 150 students interviewed, 50 applied for the computer major,60 for math and 40 for Physics.14 applied for Computer and Ma

th,13 for Math and Physics,11 for Physics and Computers and 10 applied for these 3 subjects.
What is the probability that a student chosen at random applied for:
(a)neither of the 3 subjects
(b)Math and physics but not Computers?
(c)Math given that he/she chose Computers?
Mathematics
1 answer:
scZoUnD [109]2 years ago
5 0

Answer:

C

Step-by-step explanation:

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A population of 120,000 grows 3% per year for 14 years
kobusy [5.1K]

Answer:

181510

Step-by-step explanation:

120,000 x1.03∧14=181510.767

Round the answer down as you can't have 0.767 of a person.

4 0
3 years ago
What is the value of y?
V125BC [204]

Answer:

2nd answer : 6\sqrt{3}

Step-by-step explanation:

144-36=108

\sqrt{108)= 6\sqrt{3}

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3 years ago
What is the slope of the line in the graph?​
11111nata11111 [884]

Answer:

1

Step-by-step explanation:

The slope of a line equals rise/run. That is the distance and height between each point. The horizontal and vertical distances are both 1, so 1/1= 1

5 0
2 years ago
Read 2 more answers
Mr. Sonny's science class is calculating the average number of blinks per minute. Jan blinks 57 times in 3 minutes. What is her
Vlada [557]

b. Every 24 minutes

Step-by-step explanation:

A neon sign blinks every 6 minutes, and another sign blinks every 8 minutes.

The first step is to:

Find and list multiples of each time each neon sign blinks.

This means, we find the Multiples of 6 and 8

Multiples of 6:

6, 12, 18, 24, 30, 36

Multiples of 8:

8, 16, 24, 32, 40

The first and common multiple of 6 and 8.

Therefore, the Least common multiple [LCM(6, 8) ] = 24

Hence, they often blink at the same time every 24 minutes.

Therefore, option b.Every 24 minutes is correct.

please mark me brainliest!

3 0
2 years ago
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Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx) to determine the value of the sum of three integers given: the sum of
fenix001 [56]

ffn

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

the sum of their squares is 110, So x^2+y^2 + z^2= 110

the sum of their cubes is 684, so  x^3+y^3 + z^3= 684

the product of the three integers is 210, so xyz= 210

the sum of any two products (xy+yz+zx) is 107

Now we plug in all the values in the identity

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

684 - 3(210) = (x+y+z)(110-107)

684 - 630 = (x+y+z)(3)

54 = 3(x+y+z)

Divide by 3 on both sides

18 = x+y+z

the value of the sum of three integers is 18

3 0
3 years ago
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