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4 years ago

Y = 3x - 2) what is the slope of this equation

Mathematics

2 answers:

Tatiana [17]4 years ago

7 0

I hope that’s helps you

EleoNora [17]4 years ago

6 0

Answer:

The slope is 3.

Step-by-step explanation:

So we have the equation:

$y=3x-2$

This is in the slope-intercept form, where:

$y=mx+b$

Here, m is the slope and b is the y-intercept.

From the original equation, m is 3 and b is -2.

In other words, our slope is 3.

So, the slope of the equation is 3.

And we're done!

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Why do I miss her? :/

Dima020 [189]

Answer:

because you probably liked her or you just miss her company ya know talking with her or just messing around lol

4 0

3 years ago

PLEASE HELP!!! ILL MARK A HIGH POINT COUNT, GIVE BRAINLIEST, FIVE STARS, AND GIVE THANKS TO WHOEVER ANSWERS CORRECTLY!!!!

Westkost [7]

Each letter of the alphabet is worth two times as much as the one before it, implying that the value of each letter rises in mathematical progression. The formula for finding the nth term of an arithmetic progression would be used. I am written as

a + (n - 1)d = Tn

Where

The number of terms in the arithmetic sequence is represented by n.

The common difference of the terms in the arithmetic sequence is represented by d.

The first term of the arithmetic sequence is represented by a.

Tn stands for the nth word.

Based on the facts provided,

n = 26 characters1 Equals a

3 minus 1 equals 2 (difference between 2 letters)

Therefore,

1 + (26 - 1)2 = T26

51 = T26

The formula for calculating the sum of an arithmetic sequence's n terms

is as follows:

[2a + (n - 1)d] Sn = n/2

As a result, S26 is the sum of the first 26 terms.

S26 = 20/2[2 1 + (26 - 1)2] S26 = 20/2

[2 + 50] S26 =

676 = S26 = 13 52

3 0

2 years ago

Boris choos three diffrent numbers.the sum of the three numbers is 36.One of trh numbers is a cube number.the other two number a

inna [77]

Answer:

4,5,27

Problem:

Boris chose three different numbers.

The sum of the three numbers is 36.

One of the numbers is a perfect cube.

The other two numbers are factors of 20.

Step-by-step explanation:

Let's pretend those numbers are:

$a,b, \text{ and } c$ .

We are given the sum is 36: $a+b+c=36$ .

One of our numbers is a perfect cube. $a=n^3$ where $n$ is an integer.

The other two numbers are factors of 20. $bk=20$ and $ci=20$ where $a,c,i, \text{ and } k \text{ are integers}$ .

$n^3+\frac{20}{k}+\frac{20}{i}=36$

From here I would just try to find numbers that satisfy the conditions using trial and error.

$3^3+\frac{20}{2}+\frac{20}{2}$

$27+10+10$

$47$

$3^3+\frac{20}{4}+\frac{20}{5}$

$27+5+4$

$36$

So I have found a triple that works:

$27,5,4$

The numbers in ascending order is:

$4,5,27$

4 0

3 years ago

Rewrite the quadratic function below in Standard Form. y = (x - 4) (x + 3)

Damm [24]

the standard form of a quadratic formula is

y = ax^2 + bx + c

in this case you will solve using foil method

(× - 4)(x + 3)

(x × x) +( x × 3 )(- 4 × x) ( -4)× 3))

x^2 + 3x - 4x -12

x^2 - x - 12

therefore

y = x^2- x - 12

5 0

3 years ago

It costs $107 for 10 students and $137 for 15 students. How much does it cost for 12 students?

Anestetic [448]

$\bf \begin{array}{ccccccccc}
&&\stackrel{students}{x_1}&&\stackrel{price}{y_1}&&\stackrel{students}{x_2}&&\stackrel{price}{y_2}\\
% (a,b)
&&(~{{ 10}} &,&{{ 107}}~) 
% (c,d)
&&(~{{ 15}} &,&{{ 137}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{137-107}{15-10}\implies \cfrac{30}{5}\implies \cfrac{6}{1}\implies 6$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-107=6(x-10)
\\\\\\
y-107=6x-60
\implies 
y=6x+47\\\\
-------------------------------\\\\
\textit{how much will it be for }\stackrel{x}{12~students?}\qquad y=6(12)+47$

7 0

3 years ago