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Mazyrski [523]
3 years ago
12

11 ounces is to one cup as ounces is to 10 cups.

Mathematics
2 answers:
KengaRu [80]3 years ago
6 0

Answer:

what's the question????

Step-by-step explanation:

Margaret [11]3 years ago
3 0

Answer:

What's the question?

Step-by-step explanation:

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Mr. Kuo’s checking account had a balance of $512.45
Ugo [173]

Answer:

63753.8888

Step-by-step explanation:

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3 years ago
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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
Choose all that correctly solve for the variable x
Ratling [72]
<h2>✔Answer</h2><h2>1. X = 3</h2><h2 /><h2>2. </h2><h2>\frac{7}{2}</h2><h2>3.</h2>

<h2>\frac{5}{6}</h2>

<h2>Hope it Helps❤</h2>
6 0
2 years ago
Help me please. Im giving 20 points.
borishaifa [10]

Answer:

Isn't it 54? im not really sure

Step-by-step explanation:

6x9 = 54

4 0
3 years ago
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3. How many 4-letter code can be formed using the first 10 letters of the English alphabet, if no letter can be repeated?
galben [10]
Abcdefg
There cannot be more than two because there are only two vowels, e and a. But it has to be 4 lettered, which limits a lot of option, so there can only be one 4-letter code.
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2 years ago
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