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adell [148]
2 years ago
5

Find p if 4P = 0.25​

Mathematics
2 answers:
Andrej [43]2 years ago
8 0

Answer:

p= 0.0625

Step-by-step explanation:

p=0.25/4

plz mark brainliest

MA_775_DIABLO [31]2 years ago
5 0

Answer:

p = 0.0625.

Step-by-step explanation:

4p = 0.25

Divide both sides by 4:

p = 0.25/4

p = 0.0625.

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3 years ago
Sari has a bag containing 6 half dollars. What is the mass of half dollars in Sari's bag when half dollars weighs 11.34 grams?
Fittoniya [83]
Mass of one half dollars = 11.34g
therefore mass of six half dollars = 6*11.34g
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7 0
3 years ago
Jodi poured herself a cold soda that had an initial temperature of 40degreesF and immediately went outside to sunbathe where the
kozerog [31]

Answer:

58.75 degreeF

Step-by-step explanation:

The initial temperature of the Soda = 40degreeF

The temperature outside is steady at 99 degreeF

The temperature of the soda became 50 degreeF after 8 minutes

In 8 minutes, the Soda gained

(50 - 40)degreeF

= 10 degreeF

If the soda gains 10 degreeF in 8 minutes, in 1 minute, it will gain 10/8degreeF

Therefore in 7 minutes, the soda will gain (10/8)*7

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5 0
3 years ago
Two times what equals four teen
Helen [10]

Answer:

7

Step-by-step explanation:

Set up an equation where x is the number

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x = 7

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7 0
3 years ago
Read 2 more answers
Members of the track team can run 400 min an average time of 64.6 seconds. The
vova2212 [387]

Answer:

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

Step-by-step explanation:

Calculation for the equation that can be

use to find the maximum and minimum times for the track team

Using this equation to find the maximum times for the track team

T maximum=T average -7.8 seconds

T maximum=64.6 seconds-7.8 seconds

Using this equation to find the minimum times for the the track team

T minimum=T average +7.8 seconds

T minimum=64.6 seconds +7.8 seconds

Therefore the equation for the maximum and minimum times for the track team are :

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

6 0
2 years ago
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