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2 years ago

Members of the track team can run 400 min an average time of 64.6 seconds. The

Mathematics

1 answer:

vova2212 [387]2 years ago

6 0

Answer:

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

Step-by-step explanation:

Calculation for the equation that can be

use to find the maximum and minimum times for the track team

Using this equation to find the maximum times for the track team

T maximum=T average -7.8 seconds

T maximum=64.6 seconds-7.8 seconds

Using this equation to find the minimum times for the the track team

T minimum=T average +7.8 seconds

T minimum=64.6 seconds +7.8 seconds

Therefore the equation for the maximum and minimum times for the track team are :

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

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Mrac [35]

Step-by-step explanation:

this is really complicated and tricky.

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so,

8+8 = 16

8-5 = 3

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the missing number we get then

1+6 = 7

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3×5 = 15

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giving 73155 as the next (missing) number.

control :

7+3 = 10

3-1 = 2

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5/5 = 1

gives us 10251 as next number - correct.

but then it will end

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2 years ago

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Answer:

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Step-by-step explanation:

What is <em>x</em>?

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3 years ago

8(s+3)=72 i need help it is due tomorrow

Montano1993 [528]

Answer:

s = 6

Step-by-step explanation:

8(s+3) = 72

Expand the brackets out:

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Now you get rid of 24 on the left, by taking away 24. But you also have to do the same on the right side so that both sides are equal:

8s + 24 = 72

left(-24) = right (-24)

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Now divide both sides by 8 to make them equal and to get s on its own:

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Answer:

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Step-by-step explanation:

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