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2 years ago

Answer these 4 questions for brainliest! :)

Mathematics

1 answer:

Verdich [7]2 years ago

4 0

Answer: 1. X+2

2. 6x-3

3. -2x-1

4. 9x5

Step-by-step explanation:

1. X+4-3+1 There is only one variable, so you don’t need to worry about that. Just do all of the numerical operations. 4-3+1= 2. So it would be x+2

2. X-5+5x+2. Again, do the numerical operations first. -5+2=-3. X+5x=6x. So it would be 6x-3.

3. 2x+7-4x-8. 7-8=-1. 2x-4x=-2x. So it would be -2x-1.

4. (4+3)x+2x-5. Do the operation in the parenthesis first. Then it would be (7)x or just 7x+2x-5. Simplify to 9x-5.

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HELP WILL GIVE BRANLIEST!

Natali5045456 [20]

Answer:

Since it is vertical angles, 4x - 12 = 88.

Answer is 25

Step-by-step explanation:

88 + 12 = 100

100 / 4 = 25

6 0

3 years ago

The radius of a basketball hoop is 9 inches. Which expression can be used to find the hoop's circumference in inches?

ratelena [41]

C = pi * r ^squared
r = is radius
square the radius, multiple by r
or
2 x pi x r

3 0

3 years ago

Read 2 more answers

Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probabili

ivolga24 [154]

Answer:

(a) The mean and the standard deviation for the numbers of peas with green pods in the groups of 36 is 27 and 2.6 respectively.

(b) The significantly low values are those which are less than or equal to 21.8. And on the other hand, the significantly higher values are those which are greater than or equal to 32.2.

(c) The result of 15 peas with green pods is a result that is significantly low value.

Step-by-step explanation:

We are given that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probability that a pea has green pods.

Assume that the offspring peas are randomly selected in groups of 36.

The above situation can be represented as a binomial distribution;

where, n = sample of offspring peas = 36

p = probability that a pea has green pods = 0.75

(a) The mean of the binomial distribution is given by the product of sample size (n) and the probability (p), that is;

Mean, $\mu$ = n $\times$ p

= 36 $\times$ 0.75 = 27 peas

So, the mean number of peas with green pods in the groups of 36 is 27.

Similarly, the standard deviation of the binomial distribution is given by the formula;

Standard deviation, $\sigma$ = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{36 \times 0.75 \times (1-0.75)}$

= $\sqrt{6.75}$ = 2.6 peas

So, the standard deviation for the numbers of peas with green pods in the groups of 36 is 2.6.

(b) Now, the range rule of thumb states that the usual range of values lies within the 2 standard deviations of the mean, that means;

$\mu - 2 \sigma$ = 27 - (2 $\times$ 2.6)

= 27 - 5.2 = 21.8

$\mu + 2 \sigma$ = 27 + (2 $\times$ 2.6)

= 27 + 5.2 = 32.2

This means that the significantly low values are those which are less than or equal to 21.8.

And on the other hand, the significantly higher values are those which are greater than or equal to 32.2.

(c) The result of 15 peas with green pods is a result that is a significantly low value because the value of 15 is less than 21.8 which is represented as a significantly low value.

5 0

3 years ago

ou live in the building on the left in the drawing, and a friend lives in the other building. the two of you are having a discus

Alenkinab [10]

Answer:

1.3

Friend is wrong

Step-by-step explanation:

Given:

friend's claim: height of his building is more than 1.50 times the height of yours

line of sight to the top edge of the other building makes an angle of 21° above the horizontal

line of sight to the base of the other building makes an angle of 52° below the horizontal

Solution:

Let A be the height of your building is A

Let B+A his building is B higher than yours.

Let the distance between the buildings is x.

then

tan 52 = A/x

tan 21 = B/x

A/B = tan 52 / tan 21

= 1.27994 / 0.38386

A/B = 3.33

(A + B) / A = 1.5 0

A/A + B/A = 1.50

1 + B/A = 1.50

B/A is basically (B/x) / (A/x)

1+ 3.33 / 3.33

= 4.33/3.33

= 1.3

Since 1.3 is not equal to 1.5

Hence the friend's claim is wrong.

5 0

3 years ago

Select all of the following tables which represent y as a function of x.x 5 10 11y 3 9 15x 5 10 11y 3 9 9x 5 10 10y 3 9 15

11Alexandr11 [23.1K]

Answer:

Table 1 and 2 represent a function

Step-by-step explanation:

Given

Table 1

x 5 10 11

y 3 9 15

Table 2

x 5 10 11

y 3 9 9

Table 3

x 5 10 10

y 3 9 15

Required

Determine which of the tables represent that y is a function of x

For a relation to be a function; the x values must be unique.

In other words, each x value must not be repeated;

Having said that;

Analyzing Table 1

Table 1

x 5 10 11

y 3 9 15

Note that the x rows are unique as no value were repeated;

Hence, Table 1 is a function

Table 2

x 5 10 11

y 3 9 9

Note that the x rows are unique as no value were repeated;

Hence, Table 2 is a function

Table 3

x 5 10 10

y 3 9 15

Note that the x rows are not unique because 10 was repeated twice;

Hence, Table 3 is not a function

7 0

3 years ago