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2 years ago

Answer these 4 questions for brainliest! :)

Mathematics

1 answer:

Verdich [7]2 years ago

4 0

Answer: 1. X+2

2. 6x-3

3. -2x-1

4. 9x5

Step-by-step explanation:

1. X+4-3+1 There is only one variable, so you don’t need to worry about that. Just do all of the numerical operations. 4-3+1= 2. So it would be x+2

2. X-5+5x+2. Again, do the numerical operations first. -5+2=-3. X+5x=6x. So it would be 6x-3.

3. 2x+7-4x-8. 7-8=-1. 2x-4x=-2x. So it would be -2x-1.

4. (4+3)x+2x-5. Do the operation in the parenthesis first. Then it would be (7)x or just 7x+2x-5. Simplify to 9x-5.

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Natasha2012 [34]

Answer:

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2 years ago

Find the 72nd term of the arithmetic sequence -27, -11, 5,

mixas84 [53]

Answer:

1109

Step-by-step explanation:

an = d (n - 1) + c

an = what you're looking for

n = term position

d = the common difference, in your case, 16

c = first term of the sequence, or -27

a₇₂ = 16(72 - 1) + -27 = 1109

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3 years ago

Add 7 plus 8, then add a to the result. Write an expression for the sequence of operations described.

Ipatiy [6.2K]

Answer:

(7 + 8) + a is your answer

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2 years ago

Membership in an art club is expected to grow by about 4% per month. Currently, there are 350 members in the club. In about how

igomit [66]

500=350(1+0.04/12)^12x
Solve for x
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6 0

3 years ago

Read 2 more answers

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

7 0

2 years ago