1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STALIN [3.7K]
2 years ago
9

Find the radius and diameter of circle A, if the endpoints of the radius are (-2, -1) and (6,4).

Mathematics
1 answer:
AleksandrR [38]2 years ago
8 0

Step-by-step explanation:

length \: between \: ( - 2, - 1) \: and \: (6,4) \\  =  \sqrt{(x _{1} - x  _{2} )² + (y _{1}  - y _{2})²  }  \\  =  \sqrt{( -  2 - 6)²+ ( - 1 - 4)²}  \\  =   \sqrt{64 + 25}  \\  =  \sqrt{100}  \\  = 10 \: units \\ radius = 10 \: units \\ diameter = 2 \times radius \\ d = 2 \times 10 \\ d = 20 \: units

You might be interested in
What is the 50th term of the arithmetic sequence having u(subscript)1 = -2 and d = 5
OLga [1]

Answer:

243

Step-by-step explanation:

The general term for this arithmetic sequence is:

a(n) = -2 + 5(n - 1).

Then a(50) = -2 + 5(49) =   243

8 0
2 years ago
HEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPP
zheka24 [161]
It is the third bubble
Hope i helped!
7 0
3 years ago
Read 2 more answers
The graph of f(x) = x+ was transformed to create the graph of g(x) = f(x) - 9.
Ludmilka [50]

Answer:

Step-by-step explanation:

A

3 0
2 years ago
Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
3 years ago
Work out the area of a rectangle with base, b = 34mm and perimeter, P = 86mm.​
Nana76 [90]

Answer:

306mm²

Step-by-step explanation:

the height h = 86/2 -34 = 43-34=9mm

the area = 34×9= 306mm²

8 0
2 years ago
Read 2 more answers
Other questions:
  • 1 1/3+2 2/3 mixed number
    13·2 answers
  • What is the definition for associative property of multiplication in your own words and explain how you would use it to compute
    14·2 answers
  • Solve the following equation:
    12·2 answers
  • A bookstore sells used books for $8 each. Let n represent the number of books. The cost for n books is 8 xn or 8n.
    14·1 answer
  • if the result, when solving a system by either elimination or substitution, is -5 = -5, the solution is:​
    13·1 answer
  • PLEASE HELP ASAP!!!!!!!!!!!
    7·1 answer
  • The St. Croix junior hockey
    6·1 answer
  • Can someone pleas Help me with this I don't get it. And Thank you o much if you helped me.
    6·2 answers
  • What is the measure of ∠KMN?<br> A. 29 degrees<br> B. 66 degrees<br> C. 53 degrees<br> D. 89 degrees
    9·2 answers
  • a new hospital in cedarburg starts out with 12 junior residents and 6 senior residents on its staff. management plans to hire ad
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!