Solve the following proportion 12/25=x/88

PLEASE HELP Which expression represents the difference quotient of the function f (x) = negative StartRoot 2 x EndRoot?

natali 33 [55]

Answer:

c is the correct option

Step-by-step explanation:

from,

f'(x) = h >0 f(x + h) - f(x)

h

f(x) = - √2x

f(x + h) = - √(2x + h)

f'(x) = h>0 -√(2x + h) - √2x

h

rationalize the denominator

= h>0 -√(2x + h) + √2x (-√(2x + h) - √2x)

h (-√(2x + h) - √2x)

= h>0 4x + 2h - 4x

h(-√(2x + h) -√2x)

= h>0 2h

h(-√(2x+h) - √2x)

= h>0  2 

-√(2x+h) - √2x

5 0

3 years ago

Read 2 more answers

One of the roots of the equation x²-5x +q=0 is 2. Find the other root and the value of the coefficient q.

yuradex [85]

Answer:

Other root: $x=3$

$q=6$

Step-by-step explanation:

If $x=2$ , then $x-2=0$ .

Therefore:

$x^2-5x+q=0$

$2^2-5(2)+q=0$

$4-10+q=0$

$-6+q=0$

$q=6$

This means that the other root is $x=3$ since $(x-2)(x-3)=x^2-5x+6$

5 0

2 years ago

Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12

tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12$

5 0

2 years ago

The length of a rectangle is 7 inches less than twice the width, w, of the rectangle.

Ivan

Answer:

Step-by-step explanation:

Let w represent the width of the rectangle.

The length of a rectangle is 7 inches less than twice the width, w, of the rectangle. It means that the length is (2w - 7) inches

Part A

The function that gives the area as a function of the width is

A(w) = w(2w - 7)

Part B:

If the area of the rectangle is 60 square inches, it means that

w(2w - 7) = 60

2w² - 7w = 60

2w² - 7w - 60 = 0

2w² + 8w - 15w - 60 = 0

2w(w + 4) - 15(w + 4) = 0

2w - 15 = 0 or w + 4 = 0

w = 15/2 or w = - 4

Since w cannot be negative, then

w = 15/2 = 7.5 inches

4 0

3 years ago

When instructed to find the length of HJ in right

kobusy [5.1K]

See attachement for the diagram of the triangle

Answer/Step-by-step explanation:

To find the length of HJ, we can use different equations as follows:

✔️Recall: SOHCAHTOA

Let's take <G as the reference angle = 28°

Opposite side to reference angle = HJ

Hypotenuse = 20

Apply SOH.

Thus:

Sin 28° = opp/hyp

Sin 28° = HJ/20 (Alex's equation is correct).

Solving further, we would have:

HJ = Sin 28 * 20 ≈ 9.4

✔️Another way is by using <H as the reference angle.

m<H = 180° - (90° + 28°) (sum of triangle)

m<H = 62°

Adjacent side to reference angle (<H) = HJ

Hypotenuse = 20

Apply CAH:

Cos 62° = Adj/Hyp

Cos 62° = HJ/20 (Marlene's equation is correct)

Solving further, we would have,

HJ = Cos 62° * 20 ≈ 9.4

As you can see, the equation of both students are correct. Both would arrive at the same answer using any of the two equations.

8 0

3 years ago